Question

Perform the Operation k^2+3k-10/36 × 3/k^2-4

Answer 1

Answer:

$\frac{(k+5)}{12(k+2)}$

Step-by-step explanation:

We need to perform the folowing operation:

$\frac{k^{2} + 3k - 10 }{36}$ × $\frac{3}{k^{2} -4 }$

Factorizing we have:

$\frac{(k-2)(k+5)}{36}$  × $\frac{3}{(k+2)(k-2)}$

Simplifying, we get:

$\frac{(k+5)}{12(k+2)}$