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xz_007 [3.2K]
3 years ago
7

Draw a box-and-whisker plot for these Data 5, 15, 18, 8, 12, 7, 15, 13, 10, 5, 1

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
Is the data the numbers of so then first you need to draw a table then you need to find a pattern and you should know the rest. I hoped this helped
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Which is the graph of<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20-%202" id="TexFormula1" t
Anna11 [10]

ANSWER

See attachment.

EXPLANATION

The given function is

y =  \sqrt[3]{x + 1}  - 2

The parent function is

y =  \sqrt[3]{x}

When we shift the parent graph to the left one unit, and down 2 units, we obtain the graph of the given function.

The graph of this function is shown in the attachment.

5 0
3 years ago
What is the answer to this?
a_sh-v [17]
The answer is 35 bc it has pointed on the dot
5 0
4 years ago
Correlation of a scatter plot question in image
Ierofanga [76]

Answer:

For this question there appears to be absolutely no association. The points are all over the place and there is not consistent factors at play here.

8 0
3 years ago
A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand
Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

\mu_G = 15

s_G = \frac{4.2}{\sqrt{35}} = 0.71

The distribution of life spans for electric ranges has a mean of 13.4 years and a standard deviation of 3.7 years. Sample of 40:

This means that:

\mu_E = 13.4

s_E = \frac{3.7}{\sqrt{40}} = 0.585

Which of the following best describes the sampling distribution of the difference in mean life span of gas ranges and electric ranges?

Shape is approximately normal.

Mean:

\mu = \mu_G - \mu_E = 15 - 13.4 = 1.6

Standard deviation:

s = \sqrt{s_G^2+s_E^2} = \sqrt{0.71^2+0.585^2} = 0.92

So the correct answer is given by option b.

8 0
3 years ago
What is 10.9091% to 2 decimal places
Tom [10]

Answer:

10.91%

Step-by-step explanation:

Take your number: 10.9091

Now find the first 3 decimals: 10.<u>909</u>

If the last (3rd) decimal is 5 or more raise the 2nd decimal: 10.9<u>09</u> → 10.9<u>1</u>

That is 2 decimal places

(if your teacher doesn't want it rounded then just 10.90%)

4 0
3 years ago
Read 2 more answers
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