Hello :
the center of this cercle is : O( 0, 0)
calculate the slope m of the line : OA .. A (3,-4)
m= (yA - yO) / (xA- xO)
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1 (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)
Answer:
b = 5.
Step-by-step explanation:
-3(6 + 6b) + 4 = -104
-18 - 18b + 4 = -104
-18b = -104 + 18 - 4
-18b = -90
b = -90 / -18
b = 5.
Log16 4 = 2
log base 16 then the number four then set that equal to 2
Answer:
u need to put a picture so we know what your talking about
