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Gelneren [198K]
3 years ago
5

Help me ASAP. What function is graphed below?

Mathematics
1 answer:
Delvig [45]3 years ago
5 0

Answer:

Your answer is C. Hope this helps you! :)

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22. f(x) is stretched horizontally by a factor of 2 and reflected across the x-axis. Which choice shows the correct representati
goblinko [34]

Answer:

A. -f(1/2 x)

Step-by-step explanation:

Reflextion about the x-axis is

f(x) -> -f(x)

and horizontal dilation is

f(x) -> f(-x/b) where b is the factor of dilation.

so the proper answwer is

A. -f(1/2 x)

6 0
3 years ago
Need help with number 3
marin [14]
IM THINKING B.)
HOPE ITS RIGHT LOL 
3 0
3 years ago
"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year
KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that p = 0.56

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is P(X \geq 1) when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0
3 years ago
P ( rolling a 5 or rolling a 4 ) on a die or fair number cube. Find the probability of these mutually exclusive events.​
pentagon [3]

Answer: I believe it the probability of this would be 1/3.

Step-by-step explanation: This is mainly because if the chances of rolling a 5 or a 4 on a die or fair numbered cube, which contains 6 sides, then landing on 5 or 4 would be 2 out of the six chances it would land on those two numbers. Hope this helps!

3 0
3 years ago
Find each indicated product <br>1) 2s(s-4) <br>2) (w+7) (w+3)<br>3) (x+9) (x-2) 4) (2t-1) (t+5)​
Andrej [43]

Answer:

1) 2s(s-4

Ans:

2(−4)

22−8

2)(w+7) (w+3)

Ans:

(+7)(+3)

(+3)+7(+3)

2+3+7(+3)

2+3+7+21

2+10+21

4 0
3 years ago
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