All categories

3 years ago

Which fraction is equivalent to 7/8 ?

2 answers:

7 0

Many fraction equivalent to 7/8
7/8•2=7/4
7/8•3=21/8
7/8•4=7/2
7/8•5=35/8
7/8•6=21/4
7/8•7=49/8
7/8•8=7
7/8•9=63/8
7/8•10=35/4

Maru [420]3 years ago

6 0

So from 7/8 = 35/40 , 35 is the answer

You might be interested in

Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$

The standard error is given by the following formula:

$SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

And replacing we have:

$SE=\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=3.306$

Confidence interval

Now we have everything in order to replace into formula (1):

$-15.8-2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-23.437$

$-15.8+2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-8.163$

So on this case the 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

8 0

3 years ago

In a group of 36 students, 6 study both Art and Biology.

vichka [17]

<h2>Greetings!</h2>

Answer:

$\frac{1}{6}$

Step-by-step explanation:

If the total data set is 36 students, and you need to find out the probability that the randomly selected student studies both art and biology, you need to find the ratio:

Every 36 students there is 6

36 : 6

Divide both sides by 6:

6 : 1

So that means the probability is:

$\frac{1}{6}$ or 1.16 recurring

<h2>Hope this helps!</h2>

3 0

3 years ago

The area of a triangle is 40sq inches. If the base of the triangle is 10 inches what is it’s height?

sweet [91]

Area of a triangle= 1/2 base times height
substitute

40=1/2*10*x
40=5x
x=8

the height is 8 inches