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Ad libitum [116K]
3 years ago
13

What is the minimum possible value for y in the equation y = x^2 + 12x + 5?

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

Step-by-step explanation:

hello :

y = x² + 12x + 5

y = ( x²+12x+36) -36+5

y= (x+6)²-31.......vertex form when the minimum possible value is : - 31

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For what value of 0 is cos^-1(sqrt2/2)=0?
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No Solution (i cant see the picture you attached but i can explain why.)

cos^-1(sqrt2/2)=0 is false

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Dorita's rock climbing is on a trip to Yosemite to climb El Captain. It rises 3600 feet above the valley floor in Yosemite. The
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Step-by-step explanation:

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Draw 3 distinct lines that have the same y intercept
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So y=mx+b
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4 years ago
7/19 en numero decimal​
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3 years ago
The intersection of lines y=-14x+3 and y=-32x+3 is .
Kamila [148]

The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

<h3>How to determine the intersection of the lines?</h3>

The lines are given as:

y = -14x + 3 and y = -32x+3

Substitute y = -32x+3 in

-32x+3 = -14x + 3

Evaluate the like terms

-18x = 0

Divide by -18

x = 0

Substitute x = 0 in y = -14x + 3

y = -14(0) + 3

Evaluate

y = 3

Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

Read more about linear equations at:

brainly.com/question/14323743

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