7*7=49+5=54 just use PEMDAS
So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
___________________________
S=(k+1)(k)
so the sum will be equal to
S=

so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct
Answer:
40%
Step-by-step explanation:
(21-15)/15=0.4
0.4×100=40
Answer:
1. 0.472
2. 0.25
Step-by-step explanation:
1. reduce the fraction with 3 = 1\4 + 2\9
write all numerators above the Least common denominator 36 =9 + 8\36
Add numbers = 17\36 and the alternate form is 0.472
2. Divide the numerator and denominator by three = 3 ÷ 3\12 ÷ 3 = 0.25
I can't do the others now I have an exam(sorry)
answer:
distribute
step-by-step explanation:
7(x+2)
7(x)=7x
7(2)= 14
7x+14