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Katarina [22]
2 years ago
7

Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→0 e3x − 1 −

3x x2
Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
8 0

It looks like the limit is

\displaystyle \lim_{x\to0} \frac{e^{3x} - 1 - 3x}{x^2}

L'Hôpital's rule works in this case; applying it twice gives

\displaystyle \lim_{x\to0} \frac{e^{3x} - 1 - 3x}{x^2} = \lim_{x\to0} \frac{3e^{3x} - 3}{2x} = \lim_{x\to0} \frac{9e^{3x}}{2} = \boxed{\frac92}

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