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I hope this helps I'm not exact sure
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to

, we can work backwards to add 11 to both sides. We see that

must be under the radicand, so the answer is
A.
One hundred and three million, seven hundred and twenty-seven thousand, four hundred and ninety five.
i don't understand, what is it asking for here?
I strongly recommend that you find an illustration of an ellipse that features the three distances a, b and c. You could Google "ellipse" and sort through the various illustrations that result, until you find the "right one."
There is an equation that relates a, b and c for an ellipse. It is a^2 = b^2 + c^2.
a is relatively easy to find. It is the distance from the center (0,0) of your ellipse to the right-hand vertex (20,0). So a = 20.
b is the distance from the center (0,0) of your ellipse to the right-hand focus (16,0). So b = 16. You could stop here, as it was your job to find b.
Or you could continue and find a also. a^2 =b^2 + c^2, so
here a^2 = 16^2 + 20^2. Solve this for a.