1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
3241004551 [841]
3 years ago
5

7x/z=10-r solve for x

Mathematics
1 answer:
baherus [9]3 years ago
4 0
Answer is:

x= 10z/7 - rz/7

You might be interested in
A circle centered at the origin has a radius of 10 units. The terminal side of an angle, Theta, intercepts the circle in Quadran
Tanzania [10]
Since the circle is centered at the origin, we can use the equations
x² + y² = r²
x = r cos θ
y = r sin θ

We know y = 8 and r = 10. Solving for x
x² + 8² = 10²
x = 6

From this equation:
x = r cos θ
6 = 10 cos θ
cos θ = 6/10 = 0.6
7 0
3 years ago
Answer quick for brainliest
Verizon [17]

Answer:

y=-2x+4

Step-by-step explanation:

Hello there!

Using y=mx+b, -2 is the slope and 4 is the y-intercept.

;)

7 0
3 years ago
Read 2 more answers
HELPPP MEEEE PLEASE!
Nataly [62]

Answer:

What is that

Step-by-step explanation:

I am scared of math

6 0
3 years ago
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
3 years ago
What is the least 10 digit whole number
Valentin [98]
Least 10 digit whole number = 1,111,111,111
6 0
3 years ago
Other questions:
  • Joanne buys a car for $1500 after 12 months Joanne is forced to sell the car for 10% less than what she brought it for, how much
    10·1 answer
  • If 64 feet of rope weighs 20 pounds how much will 80 feet of the same type of rope weigh?​
    5·1 answer
  • What is the sum of 8 and 7, doubled
    12·2 answers
  • Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system.
    10·1 answer
  • Choosy Chocolates sold chewy squares and chocolate stars at a ratio of 3 to 8. 45 more chocolate stars were sold than chewy squa
    15·1 answer
  • Please help! Im so dumb ( -̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥᷄ ω-̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥̥᷅ )
    8·1 answer
  • The number on two consecutively numbered gym lockers have a sum of159. what are the locker numbers. Use comma to separate the an
    8·1 answer
  • Find the range of the function
    11·1 answer
  • Which value makes the inequality r > 2.5 TRUE?
    6·1 answer
  • PLZZZZZZZZZZZZZZZZZZZZZZZZZZZ PLZ PLZ HELPPPPPPPP<br> ILL MARK BRAINLEST
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!