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3 years ago

A line contains the points (6,8), (-2, k) and (-10, 4). What is the value of k?

Mathematics

2 answers:

Alik [6]3 years ago

8 0

Answer:

k = 6

Step-by-step explanation:

Step 1: Find slope <em>m</em>

m = (4 - 8)/(-10 - 6)

m = -4/-16

m = 1/4

y = 1/4x + b

Step 2: Find <em>b</em>

4 = 1/4(-10) + b

4 = -5/2 + b

b = 13/2

Step 3: Rewrite equation

y = 1/4x + 13/2

Step 4: Find <em>k</em>

y = 1/4(-2) + 13/2

y = -1/2 + 13/2

y = 12/2

y = 6

Reika [66]3 years ago

8 0

Answer: 6

Step-by-step explanation:

As you move left to right on the x-coordinate, your y value is increasing. If you notice, the x values are increasing by eight at a time. So, if you take the value in between 4 and 8, you get your answer, which is 6.

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klemol [59]

Using it's concept, the approximate perimeter of pentagon ABCDE is given as follows:

34.4 units.

<h3>What is the perimeter of a figure?</h3>

The perimeter of a figure is given by the sum of the lengths of it's outside dimensions.

In this problem, the vertices are in a coordinate-plane, hence the distances are found using the formula for the distance between two points.

<h3>What is the distance between two points?</h3>

Suppose that we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of segment AB is:

$AB = \sqrt{(6 - 0)^2+(0 - 7)^2} = 9.2$

The length of segment BC is:

$BC = \sqrt{(6 - 3)^2+(0 + 4)^2} = 5$

The length of segment CD is:

$CD = \sqrt{(-3 -3)^2+(-4 + 4)^2} = 6$

The length of segment DE is:

$DE = \sqrt{(-6 + 3)^2+(0 + 4)^2} = 5$

The length of segment EA is:

$EA = \sqrt{(-6 +0)^2+(0 - 7)^2} = 9.2$

Hence the perimeter is:

P = AB + BC + CD + DE + EA = 9.2 + 5 + 6 + 5 + 9.2 = 34.4 units.

More can be learned about the perimeter of a figure at brainly.com/question/18610622

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2 years ago