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KATRIN_1 [288]
3 years ago
9

-4 + 4 Same signs? Different sign? Add/Subtract?

Mathematics
2 answers:
cestrela7 [59]3 years ago
8 0

Answer:

the answer is 0

Step-by-step explanation:

They cancel eachother out

      ↓∩∩ ∩∩ ↓                    

-5 -4 -3 -2 -1 0 1 2 3 4 5

I hope this was helpful1 Make sure to write a review, thank, or mark as brainliest. plz :)

marin [14]3 years ago
4 0

Answer:

Step-by-step explanation:

-4 is negative 4 witch is less then 4. -4 +4 =0

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ArbitrLikvidat [17]
Thats how u answer the question

5 0
3 years ago
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Find the equation of the line that is parallel to the given line and passes through the given point. y = −6x + 3; (5, 0) The equ
Alecsey [184]

Answer:

y= -6x+5

Step-by-step explanation:

Since the lines are parellel the lines don't intersect AT ALL so they have the same slope. Moreover, since the point given is (0,5), given so that the point is on the y-axis and the line intersects it, the y coordinate since x is zero will by the y-intercept.

Hope this Helps!!


8 0
3 years ago
If I did 8× 3\4 would the answer be 6
aivan3 [116]
Yes the answer would be 6. all you would have to do is divide 3 by 4 and get .75 then you will multiply .75 by 8
3 0
3 years ago
If two fair dice are tossed, what is the smallest number of throws, n, for which the probability of getting at least one double
amid [387]

This is a rather famous probability problem.

The easiest way to solve this is to calculate the probability that you WON'T roll a "double 6" (or a twelve) each time you roll the dice.  There are 36 ways in which dice rols can appear and only one is a twelve.  So, for one roll, the probability that you will NOT get a twelve is (35/36)^n where 35/36 is about .97222222 and n would equal 1 for the first trial.  So for your first roll the odds that you WON'T get a 12 is .97222222.

For the second roll we calculate (35/36) to the second power or (35/36)^2 which equals about .945216.

When we get to the 24th roll we calculate (.97222222)^24 which equals 0.508596.  

For the 25th roll, we calculate (.97222222)^25 which equals  0.494468.  For the first time we have reached a probability which is lower than 50 per cent.  That is to say, after 25 rolls, we have reached a point in which the probability is less than 50 per cent that we will NOT roll a twelve.

To phrase this more clearly, after 25 rolls we reach a point where the probability is greater then 50 per cent that you will roll a 12 at least once.

Please go to this page 1728.com/puzzle3.htm and look at puzzle 48. (The last puzzle on the page).  An intersting story associated with this probability problem is that in 1952, a gambler named Fat the Butch bet someone $1,000 that he could roll a 12 after 21 throws.  (He miscalculated the odds [as we know you need 25 throws] and after several HOURS, he lost $49,000!!!)

Please go that page and it has a link to the Fat the Butch story.


3 0
3 years ago
What’s the answer and how do you figure these out?
Nat2105 [25]

Answer:

55

Step-by-step explanation:

180-125=55

7 0
3 years ago
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