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3 years ago

Cab A charged $5x + 20 for a ride to the

Mathematics

1 answer:

Svet_ta [14]3 years ago

7 0

Answer:

Cab B charged more

It charged $(30-x) more

Step-by-step explanation:

Here, we want to know which of two cabs charged more for a ride from the airport to the mall.

To know the cab that charged more, we shall be substituting any same value of x in both of the fees

Let’s say x is 10

Thus 5x + 20 becomes 5(10) + 20 = 50 + 20 = 70

while 4x + 50 becomes 4(10) + 50 = 40 + 50 = 90

Clearly we can see that 4x + 50 is greater then 5x + 20, so we can conclude that 4x + 50 is a greater fee

Now since we know the one that’s higher, we can now know the value by which it is higher

That would be (4x + 50)-(5x + 20)

= 4x + 50 -5x -20

= 4x-5x + 50-20

= -x + 30 or simply 30-x

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Simplify the following expression by expanding the and collecting like terms -2 (-8x minus 4) + 3

AleksandrR [38]

Answer:

Step-by-step explanation:

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2 years ago

Consider the function f(x) = x² – 3x – 4 and complete parts (a) through (C). (a) Find f(a+h); f(a+h)-f(a) (b) Find (c) Find the

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Answer:

(a)

$f(a+h)=a^{2} +2ah+h^{2} -3a-3h-4$

(b)

$f(a+h)-f(a)=2ah+h^{2} -3h$

(c)

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Step-by-step explanation:

(a)

Simply evaluate (a+h) in the function:

$f(a+h)=(a+h)^{2} -3(a+h)-4=a^{2} +2ah+h^{2} -3a-3h-4$

(b)

Evaluate (a) in the function:

$f(a)=a^{2} -3a-4$

Using the previous answers lets calculate f(a+h)-f(a)

$f(a+h)-f(a)=a^{2} +2ah+h^{2} -3a-3h-4-(a^{2} -3a-4)=2ah+h^{2} -3h$

$\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2a+2h-3=2(7)+2h-3=2h+14-3=2h+11$

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Answer:

Step-by-step explanation:

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