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Svet_ta [14]
2 years ago
13

Solve the following equation algebraically:

Mathematics
1 answer:
Genrish500 [490]2 years ago
8 0

Answer:

the correct option is b. +5

Step-by-step explanation:

here's the solution : -

=》

4 {x}^{2}  = 100

=》

{x}^{2}  =  \frac{100}{4}

=》

{x}^{2}  = 25

=》

x =  \sqrt{25}

=》

x = 5

hence, value of x = 5

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The vector <em>v</em> (-6, 6, -5) points in the direction of itself, so we start there.

We can capture all points on the line through the origin and the point (-6, 6, -5) by scaling <em>v</em> by an arbitrary real number <em>t</em>.

The line through point <em>P</em> and pointing in the same direction as <em>v</em> is parallel to the other line that passes through the origin. Then the line we want can be obtained by translating the line through the origin by a vector <em>p</em> that points to (-4, 5, 2), so the vector equation for this line is

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<em>r </em>(<em>t </em>) = (-4 - 6<em>t</em>, 5 + 6<em>t</em>, 2 - 5<em>t</em> )

To get the parametric equations, simply take out the components:

<em>x</em> (<em>t</em> ) = -4 - 6<em>t</em>

<em>y </em>(<em>t</em> ) = 5 + 6<em>t</em>

<em>z</em> (<em>t</em> ) = 2 - 5<em>t</em>

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A company performs linear regressions to compare data sets for two similar
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Based on the information given, the thing that can be concluded is that Brand A's data are probably linear while Brand B's data are probably not.

<h3>What is a Linear regression?</h3>

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If residuals for brand A are randomly scattered above and below the x-axis, and the residuals for brand B are also randomly scattered but clustered closer to the x-axis, it implies that brand A's data are probably linear while Brand B's data are probably not.

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brainly.com/question/25987747

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Hey there!

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Answer:

Option A

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