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vekshin1
3 years ago
10

Amy just added a 462 meter run of fiber optic cable to the network what should she do next?

Computers and Technology
1 answer:
andriy [413]3 years ago
6 0

Answer:

test it.

Explanation:

Based on the information provided within the question it can be said that the next logical step after installing the 462 meter run of cable would be to test it. This is done in order to make sure that there were no malfunctions during installation and that everything is running through the cable correctly. To test the cable you must perform an end-to-end attenuation test which will verify the quality of the installation as well as ensure high quality system performance.

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Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. T
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Answer:

In C++:

#include<iostream>

#include<vector>

using namespace std;

int main() {

int len;

cout<<"Length: ";  cin>>len;

string inpt;

vector<string> vect;

for(int i =0;i<len;i++){

   cin>>inpt;

   vect.push_back(inpt); }

char ch;

cout<<"Input char: ";  cin>>ch;  

for(int i =0;i<len;i++){

   size_t found = vect.at(i).find(ch);  

       if (found != string::npos){

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       }

}  

return 0;

}

Explanation:

This declares the length of vector as integer

int len;

This prompts the user for length

cout<<"Length: ";  cin>>len;

This declares input as string

string inpt;

This declares string vector

vector<string> vect;

The following iteration gets input into the vector

<em>for(int i =0;i<len;i++){ </em>

<em>    cin>>inpt; </em>

<em>    vect.push_back(inpt); } </em>

This declares ch as character

char ch;

This prompts the user for character

cout<<"Input char: ";  cin>>ch;  

The following iterates through the vector

for(int i =0;i<len;i++){

This checks if vector element contains the character

   size_t found = vect.at(i).find(ch);  

If found:

       if (found != string::npos){

Print out the vector element

           cout<<vect.at(i)<<" ";

And move to the next vector element

           i++;

       }

}  

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