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natali 33 [55]
3 years ago
15

In parallelogram ABCD, m∠BAD=70°. Identify m∠ADC.

Mathematics
2 answers:
VashaNatasha [74]3 years ago
4 0

Answer:

The answer is B

Step-by-step explanation:

I could be wrong on this, I hope I'm not and I hope I helped!!

elena-s [515]3 years ago
3 0

Answer:

110°

Step-by-step explanation:

using angle sum property of a quadrilateral,

∠BAD+∠BCD+∠ABC+ADC=360°

LET ∠ABC=X=∠ADC

70+70+X+X= 360°

2X=360°-140°

X=220°/2=110°

∴ m∠ADC =110°

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The mean perimeter of frame = 38 cm

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Going by the illustration in the question, the perimeter is

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However, we a given the mean perimeter of the frame which are:

32 and 44. We can either choose to say; each sides is (32 by 32) and (44 by 44). Or we consider it in mean/average term as given: (32 by 44).

Case 1: To obtain the mean perimeter of the frame using the first scenario, we say:

Mean perimeter = (32+32+44+44)/4 = 38 cm.

Case 2: We can simply say:

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Graphically: Assuming that the frame is given below

                     32 cm

          ---------------------------------

         |                                      |

         |                                      |

44 cm|                                      | 44 cm

         |                                      |

         |                                      |

         |                                      |

         ----------------------------------

                       32 cm

The mean of upper frame/bars = 32 cm

The mean of side frame/bars  =  44 cm

Hence, the mean of the perimeter = (32 + 44)/2 = 38 cm

OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

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