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2 years ago

If you answer this i will give you brainlyist what is infinity x infinty bonus 2+2

Mathematics

2 answers:

Lina20 [59]2 years ago

6 0

Answer:

infinity^2

2+2=4

Step-by-step explanation:

castortr0y [4]2 years ago

3 0

Answer:

Infinity^2, 4

Step-by-step explanation:

Infinity x Infinity = Infinity^2

2 + 2 = 4

oo + oo = oooo

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The line y=2/5x +7 is dilated by a scale factor of 4 centered at the point (5,9). What equation represents the image of the lone

Serjik [45]

Answer:

Step-by-step explanation:

I don’t understand

7 0

3 years ago

(5a^2+6a+2)-(7a^2-7a-5)

krok68 [10]

For this case we must simplify the following expression: $(5a^ 2 + 6a + 2) - (7a^ 2-7a-5) =$

We eliminate the parentheses taking into account that:

$- * + = -\\- * - = +$

So:

$5a ^ 2 + 6a + 2-7a ^ 2 + 7a + 5 =$

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

$5a ^ 2-7a^2 + 6a + 7a +2 +5 =\\-2a ^ 2 + 13a + 7$

Answer:

$-2a ^ 2 + 13a + 7$

8 0

3 years ago

What is the answer to this problem 3×3+y2(16×2+7y)=

SVETLANKA909090 [29]

Your answer would be 7y^(3)+32y^(2)+9

8 0

3 years ago

Complete the missing value in the solution to the equation.^

svet-max [94.6K]

Answer:

Step-by-step explanation:

subtract 5y from both sides of the equation

6 0

3 years ago

I need help. this is the problem x^2/3+10=7x^1/3

Arlecino [84]

$\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow (x^{\frac{1}{3}})^2-7x^{\frac{1}
 {3}} +10=0 
\\\;\\
We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:
\\\;\\
t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0$

$\it \Leftrightarrow (t-2)(t-5)=0 
\\\;\\
t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8
\\\;\\
t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5 \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125$

S = {8; 125}

7 0

4 years ago