Answer:
7, I believe. I have to fill in the extra character space, so I hope you have a nice day :)
Hello.
First, let the number be r.
5 times r is written like this:
![\rm{5r}](https://tex.z-dn.net/?f=%5Crm%7B5r%7D)
Now, add 45:
![\mathrm{5r+45}](https://tex.z-dn.net/?f=%5Cmathrm%7B5r%2B45%7D)
Now, the sum of 5r+45 is equal to the sum of 85 and 140:
![\mathrm{5r+45=85+140}](https://tex.z-dn.net/?f=%5Cmathrm%7B5r%2B45%3D85%2B140%7D)
In order to solve this equation, we need to add 85 and 140:
![\mathrm{5r+45=225}](https://tex.z-dn.net/?f=%5Cmathrm%7B5r%2B45%3D225%7D)
Now, subtract 45 from both sides:
![\mathrm{5r+45-45=225-45}](https://tex.z-dn.net/?f=%5Cmathrm%7B5r%2B45-45%3D225-45%7D)
![\mathrm{5r=225-45}](https://tex.z-dn.net/?f=%5Cmathrm%7B5r%3D225-45%7D)
![\mathrm{5r=180}](https://tex.z-dn.net/?f=%5Cmathrm%7B5r%3D180%7D)
The last step is to divide both sides by 5:
![\mathrm{r=36}](https://tex.z-dn.net/?f=%5Cmathrm%7Br%3D36%7D)
Therefore, the answer is
![\rm{r=36}](https://tex.z-dn.net/?f=%5Crm%7Br%3D36%7D)
I hope it helps.
Have a nice day.
![\boxed{imperturbability}](https://tex.z-dn.net/?f=%5Cboxed%7Bimperturbability%7D)
It would be rounded down to 244 as its only .1 so its closer to 244 than it is to 245
Answer=7 minivans
45/7=6.4
since you can't have 0.4 minivans, we round up 6.4 to 7