Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:

Then we have to calculate the following limit:

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:

Hence the limit is:

Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Five hundred and sixty two divided by seven would be,
=80.28
Divide both sides by -3, and replace
with
. Then

Factorize the quadratic in
to get

which in turn means

But
for all real
, so we can ignore the first solution. This leaves us with

If we allow for any complex solution, then we can continue with the solution we ignored:

Cuz if so, then you just move the whole x term to the right side and divide all the terms on the right side by the coefficient of y
for ex...
3) 4x+4y=16
4y=16-4x (or -4x+16)
y=4-x or -x+4