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mr Goodwill [35]
3 years ago
11

The following function represents the production cost f(x), in dollars, for x number of units produced by company 1: f(x) = 0.15

x2 − 6x + 400 The following table represents the production cost g(x), in dollars, for x number of units produced by company 2: x g(x) 50 75 60 60 70 55 80 60 90 75 Based on the given information, the minimum production cost for company is greater
Mathematics
1 answer:
dsp733 years ago
5 0

Answer: g(x) at (70, 55)

Step-by-step explanation:

The minimum of g(x) is lower than f(x) which is (20, 340) and thats obviously higher than (70, 55) so :)

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Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx
Rudiy27
If we use the substitution u = \tan x, then du = \sec^2 {x}\ dx. If you try substituting just u and du into the integrand, though, you'll notice that there's a \sec^2x left over that we have to deal with.

To get rid of this problem, use the identity \tan^2 x + 1 = \sec^2 x and substitute in the left side of the identity for the extra \sec^2x, as shown:

\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx
\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx

From there, we can substitute in u and du, and then evaluate:

\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx
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8 0
3 years ago
a door with width 4.20 m has an arc as shown in diagram .Find: a) radius of the arc B) length of the arc to the nearest cm
EastWind [94]

Answer:

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Then, if the arc is at the top of the door, we will have that the diameter of that "half circle" will be equal to the width of the door.

Then the diameter of the arc is 4.20m

And the radius is defined as half of the diameter, so we have:

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And we can write this in cm (because the probelm ask for it)

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and r = 210cm, pi = 3.14

Arc = 3.14*210cm = 659.4cm

4 0
4 years ago
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