Answer:
Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)
Step-by-step explanation:
This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.
First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.
Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.
Answer:
Yes but what is the Question??\
Step-by-step explanation:
Answer:
x=-2 and x = 5
Step-by-step explanation:
The solutions to the equation are where the graph crosses the x axis
We can see that the graph crosses at x=-2 and x = 5
Answer:
im pretty sure the answer is 150
Step-by-step explanation:
hope this helps <3
Answer: 1
Step-by-step explanation:
1. 2 4/16 + 3 2/3 = 2 12/48 + 3 32/48 = 71/12 reduced is 5 11/12
( lcm of 16 and 3 is 48)
2. 6 11/12 - 5 11/12 = 1
Please give me a brainliest i did all my hard work. The answer 1 is 100% right.
