See the attached pic below
In the triangle formed by the statue and the boat, we have

and

We can solve either equation for
, then substitute that into the other equation. First, let's abbreviate
and
. Then







To find the volume of a box-shaped fish trap, we have to multiply the three dimensions of it:
(1/4 m)* (2/3 m)* (3/5 m)
= (1*2*3)/ (4*3*5) m^(3)
= 6/ 60 m^(3)
= 1/10 m^(3)
= 0.1 m^(3)
The volume of the box-shaped fish trap is 0.1 m^(3).
Hope this is helpful~
Answer:
I measures 60° ⇒ 3rd answer
Step-by-step explanation:
* Look to the attached figure
- To prove that the two triangles are similar by SAS we must to
find two proportional pairs of corresponding side and the measure
of the including angles between them are equal
- The given is:
m∠ F = 60°
EF = 40 , FG = 20
HI = 20 , IJ = 10
- To prove that the Δ EFG is similar to Δ HIJ we must to prove
# EF/ HI = FG/IJ ⇒ two pairs of sides proportion
# m∠ F = m∠ I ⇒ including angles equal
∵ EF = 40 and HI = 20
∴ EF/HI = 40/20 = 2
∵ FG = 20 and IJ = 10
∴ FG/IJ = 20/10 = 2
∵ EF/HI = FG/IJ = 2
∴ The two pairs of sides are proportion
∵ ∠ F is the including angle between EF and FG
∵ ∠ I is the including angle between HI and IJ
∴ m∠ F must equal m∠ I
∵ m∠ F = 60° ⇒ given
∴ m∠ I = 60°
* I measures 60°
C obtuse scalene
Source:
http://www.1728.org/triang.htm