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navik [9.2K]
2 years ago
15

Todd has $124 in his checking account. He wrote two checks for $13.96 and $21.67 and transferred $14 into his checking from

Mathematics
1 answer:
dangina [55]2 years ago
7 0

Answer: $74.37

Step-by-step explanation:

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What is 1/2 divided by 3 i got my Awncer but it says I got it wrong:(​
sladkih [1.3K]

Answer: A.

Step-by-step explanation:

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2 years ago
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Consider the following frequency distribution:
daser333 [38]

Answer:

        Relative frequency

        0.214

        0.268

        0.446  

        0.071

Total  1

Step-by-step explanation:

The relative frequency is computed by dividing the individual frequencies to the sum of frequencies.

sum of frequencies=12+15+25+4=56

Class     Relative Frequency

10-20       12/56=0.214

20-30      15/56=0.268

30-40      25/56=0.446

40-50      4/56=0.071

Total         12/56+15/56+25/56+4/56=56/56=1

8 0
3 years ago
Variables x and y are in direct proportion, and y = 35 when x = 2m. If x = 8m, then y =
Dmitry [639]
Y=140 because U have to go 35 divided by 2 and 8 times 17.5
8 0
2 years ago
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ms knight and ms whitaker are orgaizing their summer clothes. ms yanowitz has 6 boxes ms. whitacker has 5 boxes. they want to or
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If they have 11 boxes and 88 shorts there will be 8 shorts in each box
4 0
3 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
2 years ago
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