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Elza [17]
3 years ago
6

Find the height a 17-foot ladder can reach on the side of a building when it

Mathematics
1 answer:
labwork [276]3 years ago
3 0

Answer:

B. 15.4 ft

Step-by-step explanation:

this answer, without any formulas used, can be answered correctly and logically.

answer c, d and e are eliminated as the opposite side cant be greater than the hypotenuse.

now we have to find which is correct between a and b

the answer will be 'B' as the value of sine of an angle keeps increasing as the angle itself increases. thus, giving a bigger value of the opposite side (required height). as 15.4 ft.

mathematically,

sin65° = x/17

17 × sin65° = x

where x is height of the side of the building.

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Vladimir [108]
Given:
bottom of the plank or ground is 9 feet from the wall
length of the plant is 41 ft
height of the wall is unknown.

Let us use the Pythagorean theorem.

a² + b² = c²
a² + (9ft)² = (41ft)²
a² + 81 ft² = 1,681 ft²
a² = 1,681 ft² - 81 ft²
a² = 1,600 ft²
√a² = √1,600 ft²
a = 40 ft

The height of the wall is 40 ft.
3 0
3 years ago
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katrin2010 [14]
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3 0
3 years ago
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Can someone please help me? :)
Dimas [21]
Answer: is C. 30,000
8 0
3 years ago
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Can you please help me on this question 8(4-x)=7x+2
kati45 [8]

Answer:

2=x

Step-by-step explanation:

8(4-x)=7x+2

Distribute

32 - 8x = 7x+2

Add 8x to each side

32 - 8x+8x = 7x+8x+2

32 = 15x+2

Subtract 2 from each side

32-2 = 15x+2-2

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Divide each side by 15

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5 0
3 years ago
Simplyfy 8x^4y^5 times 10xy^3
Dennis_Churaev [7]

Answer:

80x^5y^8

Step-by-step explanation:

8x^4y^5\times 10xy^3=\\\\(8\times 10) \times (x^4\times x)\times (y^5\times y^3)=\\\\80x^5y^8

Hope this helps!

4 0
3 years ago
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