Ask question

Ask question

All categories

3 years ago

15

Please i need your help !

2 answers:

andrew11 [14]3 years ago

8 0

The answer is D the last one

romanna [79]3 years ago

4 0

Answer:

$\\ \boxed{ \huge \boxed{\tt{} Answer}}$

its the last one

$\\ \huge\boxed{\ddot\smile}$ $\\ \huge\boxed{\ddot\smile}$

You might be interested in

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

3 years ago

How many times does 48 go into 80

anastassius [24]

1.666666666666667 to be exact, but rounded it is 1.66

3 0

3 years ago

Read 2 more answers

Five twelfths ot the participants at a conference brought laptop computers with them

elena-14-01-66 [18.8K]

The number of participants with laptop is 115 and without laptop is 161

<u>Step-by-step explanation:</u>

Total number of participants= 276

Participants with laptop = (5/12) 276

= 115

Participants without laptop= 276 - 115

= 161

5 0

3 years ago

Hoover Dam, in the United States, is 223 meters high. Ertan Dam, in China, is 240 meters high. Write and evaluate a numerical ex

Black_prince [1.1K]

Your expression would be: 240-233

The correct answer is: The Ertan Dam is 7 meters higher than the Hoover Dam.

I hope this helps!
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful evening! : )

5 0

3 years ago

Cole wants to buy carpet to cover his whole living room, except for the tiled floor. The tiled floor is 4 5 6 ft by 2 1 3 ft. Fi

Shtirlitz [24]

Answer:

$Area = 49\frac{25}{36}$

Step-by-step explanation:

Given

Tile

$Length = 4\frac{5}{6}$

$Width = 2\frac{1}{3}$

See attachment for dimension of the floor

Required

Determine the area covered by the carpet

From the attachment, the dimension of the floor is:

$Length = 12\frac{1}{4}$

$Width = 5$

Calculate Area

$Area = Length * Width$

$Area = 12\frac{1}{4} * 5$

$Area = 61\frac{1}{4}$

The area of the tiles is:

$Area = 4\frac{5}{6} * 2\frac{1}{3}$

$Area = \frac{29}{6} * \frac{7}{3}$

$Area = \frac{203}{18}$

$Area = 11\frac{5}{18}$

So, the carpet area is:

$Area = Floor\ Area - Tile\ Area$

$Area = 61\frac{1}{4} - 11\frac{5}{18}$

To improper number

$Area = \frac{245}{4} - \frac{208}{18}$

Take LCM

$Area = \frac{2205 - 416}{36}$

$Area = \frac{1789}{36}$

$Area = 49\frac{25}{36}$

7 0

3 years ago