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Softa [21]
3 years ago
7

I have 22 apples and my friend has 31 how many is they’re all together?

Mathematics
2 answers:
juin [17]3 years ago
4 0
53 apples since 22 plus 31 = 53.
mrs_skeptik [129]3 years ago
3 0
The answer is 53 apples
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INSECT CONTROL Mr. Malone used 40 pounds of insecticide to cover 1,760 square feet of lawn and 60 pounds to cover an additional
arsen [322]

Answer:

101.8 lb

Step-by-step explanation:

1760 sq ft are covered by 40 lb

4480 sq ft are covered by x

1760/40 = 4480/x

1760x = 40 × 4480

x = 179,200/1760

x = 101.818181...

Answer: 101.8 lb

6 0
2 years ago
Simplify each expression.<br> -4.1 + 2n +1 +0.3n<br> What is the answer
Gnom [1K]

Answer: -4/5, in decimal form -0.8

Step-by-step explanation: −4.1+2n+1+0.3n

Combine Like Terms:

=−4.1+2n+1+0.3n

=(2n+0.3n)+(−4.1+1)

=2.3n+−3.1

=2.3n−3.1

7 0
2 years ago
Help solve #2 please
borishaifa [10]

its pithagoreon so

c^2= a^2+ b^2

c^2= 32^2 +24^2

c^2= 1,024+576

c^2= 1600

c=\sqrt{1600\\= 40

5 0
2 years ago
There are 52 weeks in a year. Ben has lived in london for two fifths of year. How many weeks has ben lived in london?
masha68 [24]

Answer:

\frac{104}{5} weeks or 20\frac{4}{5} weeks

Step-by-step explanation:

To do this we can set up a proportion

\frac{52}{1} *\frac{2}{5}

This will tell us how many weeks are in 2/5 of a year

Let's evaluate this

\frac{104}{5}

We cannot simplifiy this anymore, so we will leave it as an improper fraction, or a mixed number as shown below

20\frac{4}{5} weeks

5 0
2 years ago
Read 2 more answers
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
2 years ago
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