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andriy [413]
3 years ago
14

Simplify (x^3)(x^-2)

Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0
Hey there!

When multiplying variables with the same degree, be sure to add the two degrees being multiplied.

For example;

x * x; both of these terms have the degree of "1" as they are "x^1". Since we are multiplying them, we need to add their degrees.
x^1 * x^1 = x^2

Now that we've broken down what we are doing, let's apply this new knowledge to your problem.

(x^3)(x^-2); Remember to just add the degrees; -2 + 3 = 1
This means our product is x^1, or just x.

I hope this helps!
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Step-by-step explanation:

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quadrant 1 : both x and y are positive

quadrant 2 : x is negative, y is positive

quadrant 3 : both x and y are negative

quadrant 4 : x is positive and y is negative

(-2,4)......we have x is negative and y is positive...so we are in quadrant 2

(3,-1)....we have x is positive and y is negative...in quadrant 4

(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x

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Range = 13

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Variance = 17.61

Step-by-step explanation:

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2.) population mean (μ) :

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μ = (2 + 9 + 15 + 4 + 12 + 9 + 13 + 6 + 3 + 10) / 10

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3.) Population variance (s²)

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