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sukhopar [10]
3 years ago
9

What is the minimum point on a graph of f(x) = (x - 1)² - 3?

Mathematics
1 answer:
mariarad [96]3 years ago
8 0

Answer:

(1, -3)

First option

Step-by-step explanation:

The minimum point on the graph is also the <u>vertex</u>.

The quadratic function equation is given in <u>vertex form</u>, which is f(x) = a(x - h)^{2} + k

Using this equation, the vertex is (-h, k).

Whatever number you see for "h", find its opposite negative/positive. That will be the x-coordinate of the vertex. The y-coordinate for the vertex is the same as "k", keeping the negative and positive.

In f(x) = (x - 1)² - 3 using (-h, k) is:

h = -1   =>   -h = 1

k = -3

Therefore the vertex is (1, -3).

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