What is the minimum point on a graph of f(x) = (x - 1)² - 3?
1 answer:
Answer:
(1, -3)
First option
Step-by-step explanation:
The minimum point on the graph is also the <u>vertex</u>.
The quadratic function equation is given in <u>vertex form</u>, which is
Using this equation, the vertex is (-h, k).
Whatever number you see for "h", find its opposite negative/positive. That will be the x-coordinate of the vertex. The y-coordinate for the vertex is the same as "k", keeping the negative and positive.
In f(x) = (x - 1)² - 3 using (-h, k) is:
h = -1 => -h = 1
k = -3
Therefore the vertex is (1, -3).
You might be interested in
Answer:
- Since the question is incomplete, see the figure attached and the explanation below.
Explanation:
Since the figure is missing, I enclose the figure of a square inscribed in a circle.
Since the <em>area of a square</em> is the side length squared, you can determine the side length:
- Area = (side length)²
- 100 cm² = (side lenght)²
From the side length, you can find the diagonal of the square, which is equal to the diameter of the circle, using the Pythagorean theorem:
- diagonal² = (10cm)² + (10cm)² = 2 × (10cm)²
The area of the circle is π (radius)².
- radius = diameter/2 = diagonal/2
