What is the minimum point on a graph of f(x) = (x - 1)² - 3?
1 answer:
Answer:
(1, -3)
First option
Step-by-step explanation:
The minimum point on the graph is also the <u>vertex</u>.
The quadratic function equation is given in <u>vertex form</u>, which is
Using this equation, the vertex is (-h, k).
Whatever number you see for "h", find its opposite negative/positive. That will be the x-coordinate of the vertex. The y-coordinate for the vertex is the same as "k", keeping the negative and positive.
In f(x) = (x - 1)² - 3 using (-h, k) is:
h = -1 => -h = 1
k = -3
Therefore the vertex is (1, -3).
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Hello!
The midpoint formula is basically an average of x and y.
It is also written as: .
With the formula above, we can substitute the given points into the equation, and simplify.
Therefore, the midpoint between points H and J is choice D, (6, 3.5).
Try, please, this:
1) Imagine, that pharmacist used 'x' gr. of 40% solution and 'y' of 70% solution.
Together (20 gr. of 52% sol.) it will be x+y=20.
2) From other side, the pharmacist combined 40x and 70y gramms, after obtaining together it is 52(x+y) gramms. In other words 40x+70y=52(x+y)
3)
Answer: 8 gr. of 70% solution and 12 gr. of 40%.
1) Imagine, that pharmacist used 'x' gr. of 40% solution and 'y' of 70% solution.
Together (20 gr. of 52% sol.) it will be x+y=20.
2) From other side, the pharmacist combined 40x and 70y gramms, after obtaining together it is 52(x+y) gramms. In other words 40x+70y=52(x+y)
3)
Answer: 8 gr. of 70% solution and 12 gr. of 40%.