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sukhopar [10]
4 years ago
9

What is the minimum point on a graph of f(x) = (x - 1)² - 3?

Mathematics
1 answer:
mariarad [96]4 years ago
8 0

Answer:

(1, -3)

First option

Step-by-step explanation:

The minimum point on the graph is also the <u>vertex</u>.

The quadratic function equation is given in <u>vertex form</u>, which is f(x) = a(x - h)^{2} + k

Using this equation, the vertex is (-h, k).

Whatever number you see for "h", find its opposite negative/positive. That will be the x-coordinate of the vertex. The y-coordinate for the vertex is the same as "k", keeping the negative and positive.

In f(x) = (x - 1)² - 3 using (-h, k) is:

h = -1   =>   -h = 1

k = -3

Therefore the vertex is (1, -3).

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If you roll a fair six-sided die and a fair four-sided die, what is the probability that neither die shows a 1?
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Answer in decimal form: 0.625

==============================================

Explanation:

There are 5 sides that aren't labeled "1" out of 6 total. So the probability of not rolling a "1" on the six-sided die is 5/6

Similarly, there are 3 sides that aren't labeled "1" out of 4 sides on the four-sided die. The probability of not rolling a "1" for this die is 3/4

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