2 years ago

How to do Imaginary number

1 answer:

7 0

Here’s the chart or I think you can plug it into ur calculator. Also if it’s imaginary then there’s no real solutions

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OLEGan [10]

Y = 3sin(2x - 5)
y = 3sin(2x - 5)

6 0

2 years ago

padilas [110]

Answer:

n= 4f/5+90

Step-by-step explanation:

f= 5(n−90) /4 (simplify)

f * 4=5(n−90) (multiply 4 on both sides)

4f=5(n−90) (regroup)

4f/5 =n−90 (divide 5 on both sides)

4f/5 +90=n (add 90 to both sides)

4 0

2 years ago

Serhud [2]

Answer:

Ф = $\frac{\pi }{4} ,\frac{5\pi}{4}$

Step-by-step explanation:

It is a bit difficult to input the work here, so I uploaded an image

First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
Then we can combine like terms
Then we can factor this as a polynomial function
Then we can set each term equal to zero and solve for Ф
The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
The second term tan(Ф) - 1 = 0 has two solutions of $\frac{\pi}{4}$ and $\frac{5\pi}{4}$ so these are the solutions to the problem