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just olya [345]
3 years ago
7

What is y+5=7(x-8) written in standard form

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

<em>7x-y=61</em>

Step-by-step explanation:

The standard form is <em>Ax+By=C</em>.

Let's simplify the equation first.

1. Distribute: <em>y+5=7x-56</em>

2. Subtract 5: <em>y=7x-61</em>

3. Arrange into standard form: <em>7x-y=61</em>

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3) a+c=15; ax+cy=132
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3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B%28%20%5Csqrt%7B3%7D%20%29%7D%5E%7Bx%20%2B%20y%7D%20%20%3D%209%20%5C%5C%20%20%7B%28%20%5
algol13

<h2>\bf \purple{ \underline{Given :-}}</h2>

• \:  {( \sqrt{3} )}^{x + y}  = 9\:  \:  \: \: (i)

• \:  {( \sqrt{2} )}^{x - y}  = 32 \:  \:  \: \: (ii)

\\

<h2>\bf \purple{ \underline{To  \: Find :- }}</h2>

•   {\sf{The  \: value  \: of}} \:   \: 2x+ y.

\\

\huge\bf \purple{ \underline{Solution :- }}

\sf{From \:  equation \:  (i), }

{( \sqrt{3} )}^{x + y}  = 9

⇒ {( \sqrt{3} )}^{x + y}  =  ({ \sqrt{3} })^{4}

⇒ x + y = 4 \:  \:  \: \: (iii)

\\

\sf{From \:  the  \: equation \:  (ii)}

{( \sqrt{2} )}^{x - y}  = 32

⇒( { \sqrt{2} })^{x - y}  =(  { \sqrt{2} })^{10}

⇒x - y = 10 \:  \:  \: \: (iv)

\\

\sf{We \:  have \:  to  \: add \:  equation \:  (iii)  \: and \:  equation  \: (iv)}

x + y + x - y = 4 + 10

⇒2x = 14

⇒x = 7

\\

\sf{Subtracting \:  equation \:  (iii)  \: from  \: equation  \: (ii),  }

x  - y - x - y = 10 - 4

⇒ - 2y = 6

⇒y =  - 3

\\

\bf\therefore x = 7 \: \:  and  \: \: y =  - 3

\\

{ \sf{Th e \:  value \:  of }}= 2x +y

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:   \: =2 \times 7  + ( - 3)

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:   \: =14 - 3

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:   =11

\bf \red{Hence,  \: the  \: value \:  of  \: 2x + y  \: is  \: 11. }

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