3 years ago

Suppose f(x) = x^2 - 4. Find the graph of f(1/4x)

Mathematics

1 answer:

allsm [11]3 years ago

4 0

The graph is a parabola with a vertex at -4

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Step-by-step explanation:

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In the xy-plane, the graph of function f(x) has zeros at −5, −2, and 2. Write the polynomial function.

Alona [7]

Answer:

$f(x) = x^3 +5x^2-4x-20$

Step-by-step explanation:

Given

$Zeros: -5,-2,2$

Required

The polynomial function

If a function has a, b and c as its zeros, the function is:

$f(x) = (x - a)(x - b)(x - c)$

So, we have:

$Zeros: -5,-2,2$

$f(x) = (x - (-5))(x - (-2))(x - 2)$

Open the inner brackets

$f(x) = (x +5)(x +2)(x - 2)$

Expand the difference of two squares

$f(x) = (x +5)(x^2 - 4)$

Expand

$f(x) = x^3 +5x^2-4x-20$

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3 years ago

Suppose f(x) = x^2 - 4. Find the graph of f(1/4x)​

Suppose f(x) = x^2 - 4. Find the graph of f(1/4x)