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forsale [732]
3 years ago
14

Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I': Hexagon DEFGHI and Hexagon D prime E

prime F prime G prime H prime I prime on the coordinate plane with ordered pairs at D are 3, 5, at E 7, 5, at F 8, 2, at G 7, negative 1, at H 3, negative 1, at I 2, 2; at D prime negative 6, 2, at E prime negative 2, 2, at F prime negative 1, negative 1, at G prime negative 2, negative 4, at H prime negative 6, negative 4, at I prime negative 7, negative 1 Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'? (x, y)→(x − 9, y − 3) (x, y)→(x − 3, y − 9) (x, y)→(x + 3, y + 3) (x, y)→(x + 9, y + 9)
Mathematics
1 answer:
BigorU [14]3 years ago
8 0
We write the translation one by one:

D (3, 5)

D' (-6, 2)

That translates to: (x - 9, y - 3), because that is for passing from D to D': (3 - 9, 5 - 3) = (-6, 2).

Therefore if it is true for D and D' then, it has to be true for all others (you can check) for that rule to be true, so the correct answer is:

(x, y)→(x − 9, y − 3)
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-1/3 -(-5/12) which shows an equivalent addition expression
dem82 [27]

Answer:

-1/3 - (-5/12) = 1/12.

Step-by-step explanation:

Simpler equation:

6/12 + (-5/12) = 1/12

Or This:

6/12 - 5/12 = 1/12.

hope this helped.

5 0
3 years ago
The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man
Lady_Fox [76]

Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.

We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2

So, the area of the floor space is equal to 5.83 sq yards.

5 0
3 years ago
Can someone please help !!
irinina [24]
10 dergres that is the answer
4 0
3 years ago
THE FUNCTION! f(x) = x^2+4 is defined over the interval (-2,2). If the interval is dived into n equal parts what is the height o
Svetradugi [14.3K]

Answer:

-2+k.5/n

Step-by-step explanation:

nsnsndksksnskksnsksnsnksnwkbsbssksj sosnanskzbwkssbkwwnkwsnwosbsndosnkssneosnenkssbkssnnkbwjwoswnks

3 0
3 years ago
Find the surface area of a 7.4 cm long iron rod and 3.1 m radius
Debora [2.8K]

Answer:

144.2 cm

Step-by-step explanation:

Length of the iron rod is 7.4cm

Radius is 3.1m

Therefore the surface area can be calculated as follows

= 2πrl

= 2×3.142×3.1×7.4

= 144.2 I'm

Hence the surface area is 144.2cm

3 0
3 years ago
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