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Sergio039 [100]
3 years ago
12

Suppose you are growing lettuce in plastic trays. You found out that your lettuce culture follows a logistic growth model with r

=0.1 g/g.day and K=100 g per tray.
What is the maximal number of grams of lettuce could you harvest per day to keep your lettuce cultures at a constant size?
Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

\frac{dN}{dt}=2.5 g/day

Step-by-step explanation:

The logistic model equation is a differential equation, given by:

\frac{dN}{dt}=r\left(\frac{K-N}{K} \right)N

Now, in this particularly model the optimum yield is at K/2. This value is the population here, so N=K/2.

\frac{dN}{dt}=0.1\left(\frac{100-(100/2)}{100} \right)(100/2)

\frac{dN}{dt}=2.5 g/day

Have a nice day!

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Answer:

7/7

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Add up the amount of the marbles in total and read what color the marble they ask for the chances of. The color of marble should go first then the total of the marbles. (they could ask for more than one color so just add up both the colors given.)

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3 years ago
Helpp !! I Dont Understand This !
makvit [3.9K]
How to solve shaded regions on a trapezoid is simple.
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Next, find the area of the non shaded region, or NS.
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4 0
3 years ago
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bezimeni [28]

ANSWER

the factor <em>will </em>

<em>1</em><em>1</em><em> </em><em>is </em><em>common</em><em> </em><em>in </em><em>both </em><em>the </em><em>given </em><em>term</em>

<em>so,</em><em> </em><em>when </em><em>we </em><em>take </em><em>1</em><em>1</em><em> </em><em>from </em><em>both </em><em>term </em>

<em>it </em><em>will </em><em>left </em><em>with </em><em> </em>

<em>1</em><em>1</em><em>(</em><em> </em><em>2</em><em>+</em><em>1</em><em>)</em><em> </em>

<em>this </em><em>is </em><em>the </em><em>final </em><em>answer</em><em> </em>

<em>hope </em><em>it </em><em>helps </em><em>and </em><em>u </em><em>have </em><em>a </em><em>great</em><em> </em><em><u>day</u></em>

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i dont know i just need points for more questions sorry

Step-by-step explanation:

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3 years ago
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