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SCORPION-xisa [38]
3 years ago
10

GET A fREE 99 points! First to answer gets it!

Mathematics
2 answers:
spayn [35]3 years ago
7 0

Answer:

Hi

Step-by-step explanation:

Hello, how' life dude?

Snowcat [4.5K]3 years ago
3 0

Answer:

i'm teh second :D

Step-by-step explanation:

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Help me like now, ty <3
Alekssandra [29.7K]

Answer:

baby zoom the pic bc i am a god

:D

Step-by-step explanation:

7 0
3 years ago
Help with this question, please!
labwork [276]

Answer:

Y Intercept: 0, 2.5

X Intercept: 3.5, 0

Explanation:

An Intercept is where a line crosses an axis. A Y Intercept is for the Y axis and the X intercept is for the X axis.

Also when writing coordinates, the x coordinate comes before the y one.

Hope this helps :)

8 0
2 years ago
Type the correct answer in the box.
Pepsi [2]

Answer:

f(g(-64)) = -190

Step-by-step explanation:

The functions are not well written.

Let us assume;

f(x) = x+1

g(x) = 3x+1

f(g(x)) = f(3x+1)

Replace x with 3x+1 in f(x)

f(g(x)) = (3x+1) + 1

f(g(x)) = 3x + 2

f(g(-64)) = 3(-64) + 2

f(g(-64)) = -192+2

f(g(-64)) = -190

<em>Note that the functions are assumed but same method can be employed when calculating composite functions</em>

8 0
2 years ago
Find the unit rate.<br> 130 feet in 6.5 seconds
madam [21]

Answer:

20 feet per second

Step-by-step explanation:

130/6.5 = 20

6 0
2 years ago
Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 =
dexar [7]
Given f(x,\ y)=x^2-y^2-2 subject to the constraint x^2+y^2=16

Let g(x,\ y)=x^2+y^2.

The gradient vectors of f and g are:

\nabla f(x,\ y)=\langle2x,-2y\rangle and \nabla g(x,\ y)=\langle2x,2y\rangle

By Lagrange's theorem, there is a number \lambda, such that

\langle2x,-2y\rangle=\lambda\langle2x,2y\rangle=\langle2\lambda x,2\lambda y\rangle

\lambda=\pm1

It can be seen that f(x,\ y)=x^2-y^2-2 has local extreme values at the given region.
6 0
3 years ago
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