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tia_tia [17]
3 years ago
13

Please solve it .........​

Mathematics
1 answer:
VLD [36.1K]3 years ago
4 0

Answer:

2

Step-by-step explanation:

We must first solve the first equation to solve the second question. If we make up an answer for each variable in the first equation, it will make it easier to solve the next. Now lets say that each of the fractions will be equal to 1/3. We can then find out that x=2, y=4, and z=4012. We then have to factor the second equation's fractions. we can factor out x, y, and z out of each fraction respectively. The equations become the same as the first set, but x, y, and z instead of 1, 2 and 2006. because we know that x=2, y=4, and z=4012, we can simplify each fraction to become 2/3, and add these fractions up to equal 2.

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2 years ago
What is the sum of the polynomials?<br> (6x+7+x^2)+(2x^2-3)
Oduvanchick [21]
Hai !
6x+7+x^2+2x^2-3
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4 years ago
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podryga [215]

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3 0
3 years ago
Read 2 more answers
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8 0
4 years ago
\frac { 6 ^ { n + 2 } - 6 ^ { n } } { 6 ^ { n + 1 } + 6 ^ { n } }
amm1812
<h3>Answer:  5</h3>

Work Shown:

m = \frac{6^{n+2}-6^{n}}{6^{n+1}+6^{n}}\\\\m = \frac{6^{n}*6^2-6^{n}}{6^{n}*6^1+6^{n}}\\\\m = \frac{6^{n}*36-6^{n}}{6^{n}*6+6^{n}}\\\\m = \frac{6^{n}(36-1)}{6^{n}(6+1)}\\\\m = \frac{6^{n}(35)}{6^{n}(7)}\\\\m = \frac{35}{7}\\\\m = 5\\\\

Therefore,

\frac{6^{n+2}-6^{n}}{6^{n+1}+6^{n}}=5\\\\

3 0
2 years ago
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