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3 years ago

Please solve it .........

Mathematics

1 answer:

VLD [36.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

We must first solve the first equation to solve the second question. If we make up an answer for each variable in the first equation, it will make it easier to solve the next. Now lets say that each of the fractions will be equal to 1/3. We can then find out that x=2, y=4, and z=4012. We then have to factor the second equation's fractions. we can factor out x, y, and z out of each fraction respectively. The equations become the same as the first set, but x, y, and z instead of 1, 2 and 2006. because we know that x=2, y=4, and z=4012, we can simplify each fraction to become 2/3, and add these fractions up to equal 2.

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Need help asap I’m stuck

qwelly [4]

Answer:

None

since the slopes are equal, it's either infinite or none.

since the ratios of Ys and Xs is 1, 18/16 should be 1 to say we have infinite answers. since it's not, the is no solution at all.

3 0

2 years ago

Read 2 more answers

What is 1/3 x²+2 x=3

allsm [11]

5. if x=3 then replace x with 3. 3^2 is 9, 1/3 of 9 is 3, 3+2 = 5

3 0

3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

Can u help me with this one

koban [17]

Answer:

SU = 16

Step-by-step explanation:

SU= 8x

ST = 6x

TU = 4

SU = ST + TU = 6x + 4 = 8x

SU - ST = 8x - 6x = 2x = 4

2x = 4

x = 4/2

x = 2

SU = 8x

SU = 8(2)

SU = 16

7 0

3 years ago

Y = 3(-1)+1<br> This is my own problem

ludmilkaskok [199]

Answer: -2

Step-by-step explanation:

6 0

3 years ago

Please solve it .........​

Please solve it .........