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3 years ago

What is the sum of the polynomials? (6x+7+x^2)+(2x^2-3)

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

Hai !
6x+7+x^2+2x^2-3
6x+7+x^2+2x^2+-3
combine like terms
6x+7+x^2+2x^2+-3
(x^2+2x^2)+(6x)+(7+-3)
=3x^2+6x+4
Cheers :3

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Answer:

Part 1) The perimeter of rectangle is equal to 24 units

Part 2) The area of rectangle is equal to 32 square units

Step-by-step explanation:

Part 1) Find the perimeter of rectangle

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

where

L is the length of rectangle

W is the width of rectangle

we have

$F(-2,5),R(-2,1),O(6,1),G(6,5)$

Plot the figure to better understand the problem

using a graphing tool

see the attached figure

Remember that in a rectangle opposite sides are congruent and the measure of each interior angle is equal to 90 degrees

$FG=RO=L\\RF=OG=W$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance FG

$F(-2,5),G(6,5)$

substitute the values

$d=\sqrt{(5-5)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

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step 2

Find the distance RF

$R(-2,1),F(-2,5)$

substitute the values

$d=\sqrt{(5-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(4)^{2}+(0)^{2}}$

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step 3

Find the perimeter

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we have

$FG=RO=L=8\ units\\RF=OG=W=4\ units$

substitute

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we know that

The area of rectangle is equal to

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we have

$FG=RO=L=8\ units\\RF=OG=W=4\ units$

substitute

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