Answer:
If the variable is x, then they have x + 5 toffees altogether.
Step-by-step explanation:
There is no way to find x as it is an unknown number. "5 more than" simply means that you add 5 to x.
Answer:
x
∈
R
,
y
∈
[
−
2
,
∞
) mark brainliest please
Step-by-step explanation:
y is defined for all real values of x
domain is
x
∈
R
(
−
∞
,
∞
)
←
in interval notation
the quadratic in the form
y
=
x
2
+
c
has a minimum turning point at
(
0
,
c
)
y
=
x
2
−
2
is in this form with
c
=
−
2
range is
y
∈
[
−
2
,
∞
)
graph{x^2-2 [-10, 10, -5, 5]}
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
It's not a prime number but
Answer : 23 • 32 • 7