The value of sector KL is 52
If JM and KN are two diamters of the circle,
then they intersect at the center
The sector JK and NM are equal
Thus,
The sector JN and KM are also equal
sector KM = sector KL + sector LM
Sector JN = Sector KM
sector JN = sector KL + sector LM
125 = 6x + 4 + 8x + 9
125 = 14x + 13
14x = 125 - 13
14x = 112
x = 8
sector KL = 6x + 4
= 6(8) + 4 = 48 + 4 = 52
Therefore, the sector KL is 52
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Answer:
3
Step-by-step explanation:
its simple, just put them all in the places they havent been, there are 3 places and three students
When a jogger runs south and then turns west, we have right angle between segment 0.8 mi and segment to the west. So it is legs of the right triangle.
1.7 mi is hypotenuse.
hypotenuse² =(leg1)²+(leg2)²
1.7²=0.8² + (leg2)²
(leg2)²=1.7²-0.8² = 2.25 mi²
leg2=√(2.25 mi²)
leg2=1.5 mi
Answer is 1.5 mi.
Answer:
2x + 3y > 6 (1)
3x – 2y = 9 (2)
x + 5y = 20 (3)
From (1) and (2), we have:
(2x + 3y) - (3x - 2y) > 6 - 9
5y - x > -3 (4)
From (3) and (4), we have:
(x + 5y) - (5y - x) > 20 - (-3)
2x > 23
x > 12,5 (5)
From (3) and (5), we have:
x + 5y = 20 ⇔ 12,5 + 5y > 20
5y > 7,5
y > 1,5
So: C = 4x + 3y > 12,5 × 4 + 1,5 × 3 = 50 + 4,5 = 54,5
Conclusion: C > 54,5
Answer:
3:8
Step-by-step explanation:
6:16. Divide by the common factor, 2, so it will become 3:8, which can't be simplifyed(think of it like a fraction).
