The area of a circle is pi(radius 2) So, the radius is just half of the diameter. The radius of the baseball is 1.5 and 1.5 x 1.5 x 3.14(pi) is 7.065. Then for the softball, 3.8/2 is 1.9, and 1.9 x 1.9 x 3.14(pi) is 11.3354 then 11.3354-7.065 is 4.2704 and that rounded, is 4.3

Hope this helped!❤

3 0

3 years ago

The function f(x)=2^x and g(x)=f(x+k). If k=-5,what can be concluded about the graph of g(x)?

melamori03 [73]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
\\\\
f(x)= A\sqrt{ Bx+ C}+ D
\\\\
f(x)= A(\mathbb{R})^{ Bx+ C}+ D
\\\\
f(x)= A sin\left( B x+ C \right)+ D
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if } B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}$

$\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind

$\bf f(x)=2^x\qquad 
\begin{cases}
g(x)=f(x+k)&k=5\\
\qquad\quad f(x+5)\\
\qquad \quad 2^{x+5}
\end{cases}$

notice, in g(x)

B = 1, no change from parent

C= +2

8 0

3 years ago

Read 2 more answers

81 + 9 = 9+81<br> true or false

alina1380 [7]

Answer:

true

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7 0

3 years ago