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frosja888 [35]
3 years ago
12

If no other row matches, the router will select the ________ row as its best match. First Last either First or Last, depending o

n the circumstances neither First nor Last
Computers and Technology
1 answer:
zzz [600]3 years ago
6 0

Answer:

Last

Explanation:

Routing is a term in engineering which involves the process of selecting a path for traffic in a network or across multiple networks. It is applicable in circuit-switched networks, such as the public switched telephone network (PSTN), and computer networks, such as the Internet. It is mostly used as a term for IP Routing.

Hence, in IP Routing, the first step is comparing the packet's destination IP address to all rows, followed by selecting the nest-match row. However, If no other row matches, the router will select the LAST row as its best match.

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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Gnoma [55]

Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

Using if...else if ....else statements it prints the expected output given in the question

A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

       int bagOunces = 7;

       print_popcorn_time(bagOunces);

   }

   public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

3 0
3 years ago
your computer is running exceptionally slow. not only does it take the operating system a long time to start, but programs also
aliina [53]

You would want to check for any programs running in the background, as well as run a virus scan.

8 0
2 years ago
Using the College Registration example from Section 6.7.3 as a starting point, do the following:
andreev551 [17]

Answer:

Check the explanation

Explanation:

INCLUDE Irvine32.inc

TRUE = 1

FALSE = 0

.data

gradeAverage WORD ?

credits WORD ?

oKToRegister BYTE ?

str1 BYTE "Error: Credits must be between 1 and 30" , 0dh,0ah,0

main PROC

call CheckRegs

exit

main ENDP

CheckRegs PROC

push edx

mov OkToRegister,FALSE

; Check credits for valid range 1-30

cmp credits,1 ; credits < 1?

jb E1

cmp credits,30 ; credits > 30?

ja E1

jmp L1 ; credits are ok

; Display error message: credits out of range

E1:

mov edx,OFFSET str1

call WriteString

jmp L4

L1:

cmp gradeAverage,350 ; if gradeAverage > 350

jna L2

mov OkToRegister,TRUE ; OkToRegister = TRUE

jmp L4

L2:

cmp gradeAverage,250 ; elseif gradeAverage > 250

jna L3

cmp credits,16 ; && credits <= 16

jnbe L3

mov OkToRegister,TRUE ; OKToRegister = TRUE

jmp L4

L3:

cmp credits,12 ; elseif credits <= 12

ja L4

mov OkToRegister,TRUE ; OKToRegister = TRUE

L4:

pop edx ; endif

ret

CheckRegs ENDP

END main

3 0
3 years ago
A friend of yours started her own dog walking business. At first she only had a couple customers, and she used Word to create al
GaryK [48]
Hire more people to help type her documents, or make Batch invoices
4 0
3 years ago
Write a program that reads a list of words. Then, the program outputs those words and their frequencies. Ex: If the input is: he
Tpy6a [65]

Answer:

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

Explanation:

This program that we are told to write will be done by using python programming language/ High-level programming language.

The question wants us to write a program in which the output will be as below;

hey 1

hi 2

Mark 1

hi 2

mark 1

Just by imputing hey hi mark hi mark.

Just copy and run the code below.

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

4 0
3 years ago
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