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4 years ago

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Mathematics

1 answer:

zheka24 [161]4 years ago

3 0

Answer:

GOSH thats a bit Mcuh dont ya think

Step-by-step explanation:

Ill answer all in a sec okay in the comments give me a sec

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Paula Purchaser borrowed $500 at 12 percent for one year. She paid a $25 processing fee.

Llana [10]

500*0.12=60 interest paid
Total finance charge=60+25=85
APR=85÷500
APR=0.17*100=17%

5 0

3 years ago

Read 2 more answers

A segment has endpoints at (15,−11) and (42,−11). How many units long is the segment?

Taya2010 [7]

$\text {Length = } \sqrt{(-11+11)^2 + (42-15)^2}$

$\text {Length = } \sqrt{ (27)^2}$

$\text {Length = } 27 \text { units }$

8 0

4 years ago

A gardener is planting two types of trees. Type A is three feet and grows at a rate of 15 inches per year. Type B is four feet t

4vir4ik [10]

Answer:

2.4 years

Step-by-step explanation:

We can write two equations for each Type and equate and solve for unknown variable.

First, we need to make the initial height (in ft) to inches.

Type A:

3 feet = 3 * 12 = 36 inches

Type B:

4 feet = 4 * 12 = 48 inches

Let "t" be the number of years

For Type A, the equation would be:

36 + 15t [36 inches already and 15 inches per year]

For Type B, the equation would be:

48 + 10t [48 inches and 10 inches per year]

Now we equate and solve for "t", the time when both are same height:

$36 + 15t = 48 + 10t\\15t-10t=48-36\\5t=12\\t=\frac{12}{5}\\t=2.4$

Hence, after 2.4 years, both trees' heights would be same

7 0

4 years ago

A local bake shop sells cookies and cakes.On monday , sean bought 3 cookies and 5 cakes and spent $78.75 on tuesday , sean bough

Bond [772]

Answer:

The price of one cookie is $1.25 and the price of one cake is $15.

Step-by-step explanation:

Let $x be the price of one cookie and $y be the price of one cake.

1. On Monday, Sean bought 3 cookies and 5 cakes, then he spent $(3x+5y) and this is $78.75. Thus,

$3x+5y=78.75.$

2. On Tuesday, Sean bought 8 cookies and 2 cakes, then he spent $(8x+2y) and this is $40. Thus,

$8x+2y=40.$

3. Solve the system of two equations:

$\left\{\begin{array}{l}3x+5y=78.75\\8x+2y=40\end{array}\right.$

Multiply the first equation by 2 and the second equation by 5 and subtract them:

$2(3x+5y)-5(8x+2y)=2\cdot 78.75-5\cdot 40,\\ \\6x+10y-40x-10y=157.5-200,\\ \\-34x=-42.5,\\ \\x=\$1.25.$

Then

$8\cdot 1.25+2y=40,\\ \\2y=40-10,\\ \\y=\$15.$

8 0

3 years ago

(n2+11n+25) ÷ ( n+5) long division

zmey [24]

Answer:

$(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,R5$

Step-by-step explanation:

Synthetic division:

-5 | 1 11 25

____-5 -30

1 6 | -5

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

Long division:

n+5 | n² + 11n + 25

- n² + 5n____ <-- n

6n + 25

- 6n + 30 <-- 6

-5 | n+6

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

6 0

3 years ago