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vladimir2022 [97]
3 years ago
13

(n2+11n+25) ÷ ( n+5) long division

Mathematics
1 answer:
zmey [24]3 years ago
6 0

Answer:

(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5} or n+6,R5

Step-by-step explanation:

<u>Synthetic division:</u>

-5 | 1  11  25

____<u>-5 -30</u>

     1  6 | -5

Therefore, (n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5} or n+6,_$R$5

<u>Long division:</u>

n+5 | n² + 11n + 25

    -   <u>n² + 5n____</u> <-- n

                6n + 25

    -   <u>        6n + 30</u> <-- 6

                         -5 | n+6

Therefore, (n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5} or n+6,_$R$5

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