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3 years ago

What percent do you actually pay if 40% discount

Mathematics

1 answer:

Yanka [14]3 years ago

4 0

Answer:

60%

Step-by-step explanation:

A 40% discount means that 40% will be off, meaning you won't have to pay 40% of the original price. Therefore, you only pay 60% of the original price (100% - 40% = 60%).

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What is the arc length?

Gwar [14]

Answer:

approximately 21, when rounded to nearest tenth.

Step-by-step explanation:

First, let's find the measure of angle BAD. Angles BAD and DAC add up to 180 degrees, so 180-57= 123 degrees. Now, let's find the circumference of the circle. The circumference is diameter * π, which is 19.6(π). Then, the ratio is 123/360, so multiply 19.6(π) by 123/360, and you get 21.0381988...... which simplifies to 21 (rounded to nearest tenth)

4 0

3 years ago

Solve i don't understand it with letters

fredd [130]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

y = $\frac{f}{kr}$

8 0

3 years ago

Read 2 more answers

#24, i am getting <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%26%5Cfrac%7B18%7D%7B7%7D%20

sveticcg [70]

It looks like you're talking about row-reducing an augmented matrix to solve the system of equations. Your answer is almost correct. The last row should read 0, 0, 1, 2/7.

The given system translates to

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 1 & -1 & 2 & 2 \\ 1 & 2 & -3 & 4 \end{array} \right]$

Eliminate x from the last two rows by combining -2 (row 2) and row 1, and -2 (row 3) and row 1; that is,

(2x - 3y + z) - 2 (x - y + 2z) = 2 - 2 (2)

2x - 3y + z - 2x + 2y - 4z = 2 - 4

-y - 3z = -2

and

(2x - 3y + z) - 2 (x + 2y - 3z) = 2 - 2 (4)

2x - 3y + z - 2x - 4y + 6z = 2 - 8

-7y + 7z = -6

In augmented matrix form, this step yields

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & -7 & 7 & -6 \end{array} \right]$

I'll omit these details in the remaining steps.

Eliminate y from the last row by combining -7 (row 2) and row 3 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 28 & 8 \end{array} \right]$

Multiply the last row by 1/28 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate z from the second row by combining 3 (row 3) and row 2 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & 0 & -8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the second row by -1 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate y and z from the first row by combining 3 (row 2), -1 (row 3), and row 1 :

$\left[ \begin{array}{ccc|c} 2 & 0 & 0 & 36/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the first row by 1/2 :

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 18/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

8 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t^3 - 21t^2 + 60t + 3 for t ≥ 0. Find the position

avanturin [10]

Your first and second derivatives which are the velocity and the acceleration respectively are correct.
The particle has reverses direction when v(t) ≤ 0 so at interval 2 < t < 5 sec.
You can substitute now t = 2 for s(2) and a(2) for first changing direction. Also t = 5 for s(5) and a(5) for second changing direction.

6 0

4 years ago

Answer choice C.) square root 3/2

disa [49]

Sine 60* = 0.86602540378

The answer that results in this number is √3/2

6 0

3 years ago