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pashok25 [27]
3 years ago
13

Outside a​ home, there is a 4​-key keypad with letters Upper A comma Upper B comma Upper C comma and Upper D that can be used to

open the garage if the correct four​-letter code is entered. Each key may be used only once. How many codes are​ possible?
Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

24 possible codes

Step-by-step explanation:

If every letter may be used only once, we can calculated how many codes are possible using the rule of multiplication as:

__4____ * ___3____ *  ____2____ * ___1______ = 24

1st letter     2nd letter      3rd letter       4th letter

Because for the 1st letter of the code, we have 4 options, letter A, B, C and D.

Then for the 2nd letter, we only have 3 options because we can not choose the letter that we choose in the 1st letter.

So, the 3rd letter just have 2 options and finally, there is just one option for the 4th letter.

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They have 5 3/4 ft

4+1=5
1/4+2/4=3/4


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Answer:

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Step-by-step explanation:

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3 years ago
Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 10, the sum of the square
professor190 [17]

Answer:

The sum of two numbers is 7.

Step-by-step explanation:

Given : the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

Using identity (x+y)(x^2-xy+y^2)=x^3+y^3 and given details, we have to find the sum of two numbers.

Since, given that the product of the numbers is 10 that is xy=10

Also, given the sum of the squares of the numbers is 29 that is x^2+y^2=29

and the sum of the cubes of the numbers is 133 that is x^3+y^3=133

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Answer:

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