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pashok25 [27]
3 years ago
13

Outside a​ home, there is a 4​-key keypad with letters Upper A comma Upper B comma Upper C comma and Upper D that can be used to

open the garage if the correct four​-letter code is entered. Each key may be used only once. How many codes are​ possible?
Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

24 possible codes

Step-by-step explanation:

If every letter may be used only once, we can calculated how many codes are possible using the rule of multiplication as:

__4____ * ___3____ *  ____2____ * ___1______ = 24

1st letter     2nd letter      3rd letter       4th letter

Because for the 1st letter of the code, we have 4 options, letter A, B, C and D.

Then for the 2nd letter, we only have 3 options because we can not choose the letter that we choose in the 1st letter.

So, the 3rd letter just have 2 options and finally, there is just one option for the 4th letter.

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The bearing of the individuals from each other are as indicated below;

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<h3>What is bearing of Henley from Dinder?</h3>

It follows from the task content that the bearing of the individuals from each other are expected to be determined.

a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.

b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.

c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.

d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.

e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.

f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.

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