Set up a system of equations:
2x+3y=6
x-3y=9
You can solve this with elimination by adding the two equations together:
3x+0y = 15
3x=15
x=5
Then, plug this value back into either of the original equations to find the y value:
5-3y=9
-3y=4
y= -4/3
The point of intersection is (5,-4/3)
Answer:
15
Step-by-step explanation:
since c is the centroid, therefore PX=XQ=1/2 x PQ
∴ PX=15
Answer:
i dont know can you turn your sceen so i can see it better
Step-by-step explanation:
Answer:
(3, 2), (6, 4)
Step-by-step explanation:
Since one end (A) of the segment AB is at the origin, the required points will be 1/3 and 2/3 of the coordinates of B:
(1/3)(9, 6) = (3, 2)
(2/3)(9, 6) = (6, 4)
Answer: y = 3x/4 + 22
Step-by-step explanation:
The equation of line l is -3y + 4x = 9
-3y + 4x = 9
3y = 4x -9
y = (4x -9)/3= 4x/3 - 3
From the slope-intercept equation,
y = mx +c
Where m= slope
Comparing both equations, we have
m = 4/3
If the new line that parallel to line l, that means they have the same slope
So, slope if new line is 3/4.
Points =(-12, 6)
From y = mx + c
x = -12,y = 6
6= 4/3 × -12 + c
6 = -16 + c
c = 6 + 16 = 22
Therefore
The equation of the line that is parallel to line l and passes through the point (-12,6) ,
y = 3x/4 + 22