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4 years ago

5

Add 0.337 + 29.4=

: 0.337 + 29.4 = " alt="add \: 0.337 + 29.4 = " align="absmiddle" class="latex-formula">

1 answer:

Daniel [21]4 years ago

5 0

If you add 0.337 and 29.4 you get 29.737

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Free_Kalibri [48]

Answer:

Area is 1,256.64 (1,256.637 if not rounded) not sure about last part. sorry

Step-by-step explanation:

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3 years ago

Read 2 more answers

The function f(x) = x2 + 10x - 3 written in vertex form is f(x) = (x + 5)2 – 28. What are the coordinates of the vertex?

alina1380 [7]

Answer:

<h2>(-5, -28)</h2>

Step-by-step explanation:

The vertex form of a quadratic function <em>f(x) = ax² + bx + c</em>:

f(x) = a(x - h)² + k

(h, k) - coordinates of a vertex

We have <em>f(x) = x² + 10x - 3</em> in the vertex form <em>f(x) = (x + 5)² - 28</em>.

f(x) = (x - (-5))² + (-28) → h = -5, k = -28

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3 years ago

Help me on question one

Sonja [21]

8*3 1/4
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(8*13)/4
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6 0

3 years ago

1/2(3g-2)=g/2 what is the answer

umka21 [38]

1/2(3g-2)=g/2
(3g-2)/2=g/2
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6g-4=2g
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4 0

4 years ago

The length of a rectangular pool is to be four times its width and a sidewalk 6ft wide will surround the pool. If a total area o

natita [175]

Answer:

52 feet by 13 feet.

Step-by-step explanation:

Given:

The length of a rectangular pool is to be four times its width.

Sidewalk is 6 feet wide will surround the pool.

If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk.

Question asked:

What are the dimensions of the pool?

Solution:

Let width of a rectangular pool = $x$

Then the length of a rectangular pool will be = $4x$

$Area\ of \ rectnagle= length\times breadth$

$=x\times4x\\ \\ =4x^{2}$

Combined length of pool and the sidewalk = length of pool + width of sidewalk + width of sidewalk

Combined length of pool and the sidewalk = $4x+6+6=4x+12$

Similarly, Combined width of pool and the sidewalk = $x+6+6=x+12$

Combined area of pool and the sidewalk = 1600

$Combined\ lengthh\times Combined\ r=breadth=1600\\ \\ (4x+12)(x+12)=1600\\ \\ 4x(x+12)+12(x+12)=1600\\ \\ 4x^{2} +48x+12x+144=1600\\ \\ 4x^{2} +60x+144=1600$

Subtracting both sides by 144

$4x^{2} +60x=1456\\ \\ 4x^{2} +60x-1456=0\\ \\ Taking\ 4\ as\ common\\ \\ x^{2} +15x-364=0\\ \\ x^{2} +28x-13x-364=0\\ \\ x(x+28)-13(x+28)=0\\ \\ x+28=0,x-13=0\\ \\ x=-28,x=13$

Since dimensions can never be in negative, hence $x=13$

Width of a rectangular pool = $x$ = 13 feet

The length of a rectangular pool will be = $4x$ = $4\times13=52\ feet$

Therefore, the dimensions of the pool are 52 feet by 13 feet.

8 0

3 years ago