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gladu [14]
3 years ago
13

Hi can any body help me please

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

nah

Step-by-step explanation:

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If cos(θ)= -2/3 and θ lies in quadrant II, find the value of cotθ
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\text{Given that,}\\\\\cos \theta = - \dfrac 23\\\\\implies \cos^2 \theta  = \dfrac 49\\\\\implies 1- \sin^2 \theta = \dfrac 49\\\\\implies \sin^2 \theta =1-\dfrac 49\\\\\implies \sin^2 \theta =\dfrac 59\\\\\\\text{Now,}\\\\\cot^2 \theta = \dfrac{\cos^2 \theta}{\sin^2 \theta} \\\\\\\implies \cot^2 \theta = \dfrac{\tfrac 49}{\tfrac 59}\\\\\\\implies \cot^2 \theta = \dfrac 49 \times \dfrac 95\\\\\\\implies \cot^2 \theta = \dfrac 45\\\\\\

\implies \cot \theta = \pm\sqrt{\dfrac 45} =  \pm \dfrac 2{\sqrt 5}\\\\\\\text{Since}~ \theta ~ \text{lies in the second quadrant,}  \cot \theta ~\text{will be negative.}\\\\\text{Hence,}~ \cot \theta = - \dfrac{2}{\sqrt 5}

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2 years ago
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What is 4.62 expressed as an improper fraction in simplest form? Enter your answer in the box.
Ket [755]
The answer is 231/50
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3 years ago
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Calculate 10% of 80. show work
Setler [38]

Answer:

8

Step-by-step explanation:

Solution for What is 10 percent of 80:

10 percent * 80 =

( 10:100)* 80 =

( 10* 80):100 =

800:100 = 8

4 0
3 years ago
A sandbox has a volume of 330 cubic feet of sand. If the sandbox is 3 feet tall, and 10 feet wide, what is the length of the san
Digiron [165]

Answer:

We are given that the total volume of the sandbox is 330 cubic feet.
We are given the side measurements of 3 feet tall and 10 feet wide.
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330 ft3 divided by 30 sq2 = 11ft

In conclusion, the length of the box would be:
= 11 ft



Step-by-step explanation:

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#TheWizzer

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