<span>The product of a fraction and 7 is greater than 7, if fraction i a/b then </span>(a/b)*7>7
The denominator 7 means (a/7), so we can rewrite (a/b)*7>7 as
(a/7)*7>7, from this inequality we get
a>7,
so the numerator is greater than 7
(3n - 2m)^2 \\ \\ (3n)^2 - 2 \times 3n \times 2m + (2m)^2 \\ \\ 3^2n^2 - 2 \times 3n \times 2m + (2m)^2 \\ \\ 9n^2 - 2 \times 3n \times 2m + (2m)^2 \\ \\ 9n^2 - 2 \times 3n \times 2m + 2^2m^2 \\ \\ 9n^2 - 2 \times 3n \times 2m + 4m^2 \\ \\ 9n^2 - 12mn + 4m^2
The final result would be, 9n² - 12mn + 4m².
Answer:
Step-by-step explanation:
ƒ.(x) = x⁷ + 3
Rename f.(x) as y
y = x⁷ + 3
Solve for x :
x⁷ = y - 3
Take the seventh root of each side
Switch x and y
Rename y as the inverse function
Answer:x=8
Step-by-step explanation:
6x+9=57
-9 -9
6x=48
6×/6=48/6
×=8
NO. You cannot subtract 3x from 6, since they are NOT like terms.
You can think of it as the 6 does not have an x term, but in 3x, there is an x term.