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Soloha48 [4]
3 years ago
14

A=1/2bh solve for b.

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

2A /h = b

Step-by-step explanation:

A=1/2bh

Multiply each side by 2

2A = 2*1/2bh

2A = bh

Divide each side by h

2A/h = bh/h

2A /h = b

cupoosta [38]3 years ago
6 0

Step-by-step explanation: First, get rid of the fraction by

multiplying both sides of the equation by 2.

That gives us 2A = bh.

Don't be thrown off by the capital A in this problem.

Just treat it like any other variable.

To get b by itself on the right side of the equation, we now simply

divide both side of the equation by h and our answer is 2A/h = b.

Take a look back at the formula now in the original problem.

Does it look familiar?

It's the formula for the area of a triangle.

Take a look at the image I have provided below.

I have made the "b" purple so you

can see that we are solving for it.

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SAS

you see RT = RT

angle TRU = angle RTU

RU = TV

4 0
3 years ago
If the endpoints of AB have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of AB?
pickupchik [31]
The midpoint, if the endpoints are (x₁,y₁) and (x₂,y₂):
(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

(9,8) \\&#10;x_1=9 \\ y_1=8 \\ \\&#10;(-1,-2) \\&#10;x_2=-1 \\ y_2=-2 \\ \\&#10;\frac{x_1+x_2}{2}=\frac{9-1}{2}=\frac{8}{2}=4 \\&#10;\frac{y_1+y_2}{2}=\frac{8-2}{2}=\frac{6}{2}=3

The midpoint of AB is (4,3).
5 0
3 years ago
Read 2 more answers
If you flip a coin and roll a 6-sided die, what is the probability that you will flip a tails and roll at least a 2?
Finger [1]

Step-by-step explanation:

Flipping a tails and rolling at least a tail are 2 independent events: they don't affect each other. So, to get the probability of both happening, we just need to multiply the probability of one by the probability of the other. he probability of rolling at least a 2 is 5/6.

4 0
3 years ago
Which expression is equivalent to 36x2 − 25? Pick One
kondaur [170]

Answer:

Your answer is D.

36x2-25 is equivalent to (6x)2-(5)2

Step-by-step explanation:

Simple solution: Put each equation into a graphing calculator and look at the tables, they are exactly the same.

6 0
3 years ago
Read 2 more answers
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
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