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Grace [21]
3 years ago
12

Solve the equation, m + 55 +1 = m =

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Steps to solve:

m + 55 + 1 = m

~Simplify

m + 56 = m

~Subtract m to both sides

56 = 0

No solution

Best of Luck!

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Two geometrically similar jugs have volumes of 1000 cm3and 512 cm3.They have circular bases. The diameter of the base of the lar
Aleks [24]

Complete Question

Two geometrically similar jugs have volumes of 1000 cm³and 512 cm³.They have circular bases. The diameter of the base of the larger jug is 9 cm.

Calculate the diameter of the smaller jug.

Answer:

7.2 cm

Step-by-step explanation:

To solve the above question,we have the proportion

Smaller volume/ Larger volume = (Smaller diameter/ Larger diameter)³

We are to find the smaller diameter

Hence our formula is give as

Cube root(Smaller volume/ Larger volume)= Smaller diameter/ Larger diameter

=cube root( 512/1000) = x/9

= 8/10 = x/9

Cross Multiply

10x = 8 × 9

10x = 72

x = 72/10

x = 7.2cm

Therefore, the diameter of the second jug is 7.2 cm

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No links Lean's mother paid 2.16 for 3 pounds of sugar. How much would 1 pound of sugar cost???
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Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in
Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.

Divide both sides of equation (II) by 5 so our numbers become smaller

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.

Rearrange (I) to solve for y so that we can substitute into (II)

\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}

Substituting this into equation (II) for the y:

\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

y = 38 - 32 = 6

32 five-dollar bills and 6 ten-dollar bills

7 0
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