What is the equation of a line that passes through 0,5 and 4,8

1 answer:

3 0

Y=3/4x+5
We know the y intercept is 5 because we have the point (0,5)
The line moves four to the right and 3 up
Slope=y/x
Slope=3/4

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Please help. Find the value of x. Round to

Law Incorporation [45]

Answer:

$x =13.7$

Step-by-step explanation:

Given

See attachment

Required

Find x

The relationship between x, 47 and $17^{\circ}$ is:

$sin(17^{\circ}) = \frac{x}{47}$

i.e.

$sin(\theta) = \frac{Opposite}{Hypotenuse}$

Solving further:

$sin(17^{\circ}) = \frac{x}{47}$

Make x the subject

$x = 47 * sin(17^{\circ})$

$x = 47 * 0.2924$

$x =13.7428$

$x =13.7$ --- approximated

3 0

3 years ago

1)calculate please it 2) prove it please

Dvinal [7]

1. 2sin²(-2490) + tan(1410)
2(0.25) - 0.6
0.5 + 0.6
1.1

2. $\frac{2sin(\alpha)cos(\beta) - sin(\alpha - \beta)}{cos(\alpha - \beta) - 2sin(\alpha)sin(b)} = tan(\alpha + \beta)$
   $\frac{2sin(\alpha)cos(\beta) - sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)}{cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta) - sin(\alpha)sin(\beta)} = tan(\alpha + \beta)$
   $\frac{sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)}{cos(\alpha)cos(\beta) - sin(\alpha)sin(\beta)} = tan(\alpha + \beta)$
   $\frac{sin(\alpha + \beta)}{cos(\alpha + \beta)} = tan(\alpha + \beta)$
   $tan(\alpha + \beta) = tan(\alpha + \beta)$