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2 years ago

1)calculate please it 2) prove it please

Mathematics

1 answer:

Dvinal [7]2 years ago

4 0

1. 2sin²(-2490) + tan(1410)
2(0.25) - 0.6
0.5 + 0.6
1.1

2. $\frac{2sin(\alpha)cos(\beta) - sin(\alpha - \beta)}{cos(\alpha - \beta) - 2sin(\alpha)sin(b)} = tan(\alpha + \beta)$
   $\frac{2sin(\alpha)cos(\beta) - sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)}{cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta) - sin(\alpha)sin(\beta)} = tan(\alpha + \beta)$
   $\frac{sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)}{cos(\alpha)cos(\beta) - sin(\alpha)sin(\beta)} = tan(\alpha + \beta)$
   $\frac{sin(\alpha + \beta)}{cos(\alpha + \beta)} = tan(\alpha + \beta)$
   $tan(\alpha + \beta) = tan(\alpha + \beta)$

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Professor Liu gave the same quiz to the students in her morning class and in her afternoon class. The average (arithmetic mean)

natka813 [3]

Answer:

Afternoon class has more students.

Step-by-step explanation:

Let m be the number of students in the morning class and n be the number of students in the afternoon class.

The average score for the students in the morning class was 80, then the sum of their scores is $80m.$

The average score for the students in the afternoon class was 86, then the sum of their scores is $86n.$

The sum of the scores of both classes is

$80m+86n$

and the average score is

$\dfrac{80m+86n}{m+n}$

The average (arithmetic mean) score for the two classes combined was 84, then

$\dfrac{80m+86n}{m+n}=84\\ \\ 80m+86n=84m+84n\\ \\86n-84n=84m-80m\\ \\2n=4m\\ \\n=2m$

This means n is greater, so afternoon class has more students.

7 0

2 years ago

(question 4 only plz)

Hatshy [7]

#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks

a) P(white) = $\frac{2}{6} = \frac{1}{3}$
P(red) = $\frac{1}{6}$
P(purple) = $\frac{3}{6} = \frac{1}{2}$

b)Not white block:
1 - $\frac{1}{3}$ OR $\frac{1}{2} + \frac{1}{6}$
$\frac{2}{3}$ $\frac{2}{3}$
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.

c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12

P(white)= $\frac{4}{12}$ which is still $\frac{1}{3}$

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12

P(purple)= $\frac{5}{12}$
(im not quite sure if my explanation here helps you though)

e) 1 more of white and purple, 5 more of red
white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)

P(red)= $\frac{6}{12}$ = $\frac{1}{2}$

5 0

2 years ago

ANSWER QUICK PLEASE!!!! BRAIN LIST AND POINTS

wel

Answer:

x = 9

Step-by-step explanation:

The two angles are alternate exterior and has same measurement

15(x+1) = 150 divide both sides by 15

x + 1 = 10 subtract 1 from both sides

x = 9

8 0

2 years ago

If 2a/4=b/4 and b≠0, what does 5b equal in terms of a?

dedylja [7]

Step-by-step explanation:

you must have made a typo here.

none of the answer options are correct for the given problem.

let me just show you what you told me, and how I can solve at least this :

2a/4 = b/4

this simply means (multiply both sides by 4) :

2a = b

so, 5b is then (multiplying both sides by 5) :

5×2a = 5b

10a = 5b

but again, "10a" is not among the offered answers.

so, I don't know if you made a mistake with the basic problem or with the answer options.

8 0

1 year ago

Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.

dalvyx [7]

Answer:

The measure of the side $QR$ is 8.8.

Step-by-step explanation:

Since $LMNO \sim PQRS$ , then $SP \propto OL$ , $RS \propto ON$ , $RQ \propto MN$ and $QP \propto LM$ . From figure we have the following relationship: