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mafiozo [28]
3 years ago
15

1)calculate please it 2) prove it please

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0
1. 2sin²(-2490) + tan(1410)
   2(0.25) - 0.6
   0.5 + 0.6
   1.1

2. \frac{2sin(\alpha)cos(\beta) - sin(\alpha - \beta)}{cos(\alpha - \beta) - 2sin(\alpha)sin(b)} = tan(\alpha + \beta)
    \frac{2sin(\alpha)cos(\beta) - sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)}{cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta) - sin(\alpha)sin(\beta)} = tan(\alpha + \beta)
    \frac{sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)}{cos(\alpha)cos(\beta) - sin(\alpha)sin(\beta)} = tan(\alpha + \beta)
    \frac{sin(\alpha + \beta)}{cos(\alpha + \beta)} = tan(\alpha + \beta)
    tan(\alpha + \beta) = tan(\alpha + \beta)
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A dolphin dove 31 meters below the surface of the water to reach a fish. It traveled 16% of the total distance every second.
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It traveled 14.88 meters after 3 seconds

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A company makes and sells charm bracelets. The cost of producing x bracelets is represented by the function
Serggg [28]

P(x) = 12x – 180

Given:

A company makes and sells charm bracelets.

The cost of producing x bracelets is represented by the function C(x) = 180 +

8x

The revenue earned from selling x bracelets is represented by the function

R(x) = 20x.


Explanation of terms:

For x bracelets,

Cost of production is C(x); C(x) = 180 + 8x

Revenue earned is R(x); R(x) = 20x.Profit made is P(x); P(x) is unknown

Profit made = Revenue earned – Cost of production

∴ P(x) = R(x) – C(x)

P(x) = 20x – (180 + 8x)

P(x) = 20x – 180 – 8x

P(x) = 12x – 180

The profit made from selling x bracelets is represented by the function

<em> P(x) = 12x – 180</em>



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3 years ago
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THe halloween haunt estimated they would make $125,450 this year. They expect to make 23,700 more than last year by the time the
sveticcg [70]

Answer:

it is at least $300000 good luck

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2 years ago
Consider the following operations on the number 8.82 x 10^-2. Without using a calculator, decide which would give a significantl
Ksenya-84 [330]

Correct question is;

Consider the following operations on the number 8.85 x 10^(-2). Without using a calculator, decide which would give a significantly smaller value than 8.85 x 10^(-2), which would give a significantly larger value, or which would give essentially the same value.

A) 8.85 × 10^(-2) + 6.69 × 10^(5)

B) 8.85 x 10^(-2) - 6.69 x 10^(5)

C) 8.85 x 10^(-2) x 6.69 x 10^(5)

D) 8.85 × 10^(-2) ÷ 6.69 × 10^(5)

Answer:

Option A & B yield essentially the same value.

Option C yields a significantly smaller value

Option D yields a significantly larger value

Step-by-step explanation:

Since given value for the operations is in 10^(-2) indices, then let's convert the operations numbers from 10^(5) indices to 10^(-2).

Thus;

6.69 × 10^(5) = (6.69 × 10^(-7)) × 10^(-2)

Thus;

A) 8.85 × 10^(-2) + 6.69 × 10^(5) is now;

8.85 × 10^(-2) + ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 + (6.69 × 10^(-7))] × 10^(-2)

The 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same

B) 8.85 x 10^(-2) - 6.69 x 10^(5) is now;

8.85 × 10^(-2) - ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 - (6.69 × 10^(-7))] × 10^(-2)

Again the 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same.

C) 8.85 x 10^(-2) x 6.69 x 10^(5) is now;

(8.85 × 10^(-2)) × ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 × (6.69 × 10^(-7))] × 10^(-2)

When we multiply 8.85 by 6.69 × 10^(-7), the value gotten will be way lower than the initial value of 8.85.

Thus,this operation will give a significantly smaller value.

D) (8.85 × 10-2) ÷ (6.69 × 10^5) is now;

(8.85 × 10^(-2)) ÷ ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 ÷ (6.69 × 10^(-7))] × 10^(-2)

When we carry out the operation:

8.85 ÷ (6.69 × 10^(-7)), it is essentially equal to (8.85 × 10^(7))/6.69.

This means that the new value would be significantly larger than the initial value of 8.85.

Thus,this operation yields a significantly larger value.

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Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:
tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

  • 91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

  • 79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

Q1 = \frac{N +1}{4}th

So, we have:

Q1 = \frac{13 +1}{4}th

Q1 = \frac{14}{4}th

Q1 = 3.5th

This is the average of the 3rd and the 4th element

Q1 = \frac{1}{2} \times (84 + 91)

Q1 = 87.5

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

Q3 =  3 \times \frac{N +1}{4}th

So, we have:

Q3 =  3 \times \frac{13 +1}{4}th

Q3 =  3 \times 3.5th

Q3 =  10.5th

This is the average of the 10th and the 11th element.

Q_3 =\frac12 \times (98 + 101)

Q_3 =99.5

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

IQR = Q_3 -Q_1

IQR = 99.5 - 87.5

IQR = 12

Also, we have:

IQR(1.5) = 12 \times 1.5

IQR(1.5) = 18

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

Lower = Q_1 - IQR(1.5)

Lower = 87.5- 18

Lower = 69.5

Upper = Q_3 + IQR(1.5)

Upper = 99.5 + 18

Upper = 117.5

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0
2 years ago
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