Answer:
The correct option is (C).
Step-by-step explanation:
According to the Central Limit Theorem if we have n unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample means is given by,

And the standard deviation of the distribution of sample means is given by,

The information provided is:
<em>μ</em> = 3.5
<em>σ</em> = 1.7078
<em>n</em> = 400 = number of times the experiment is repeated.
As the sample size is quite large, i.e. <em>n</em> = 400 > 30 the central limit theorem can be used to approximate the sampling distribution of the sample mean.
The mean of the distribution of sample means is:

The standard deviation of the distribution of sample mean is:

The distribution of the sample mean is:
.
Thus, the correct option is (C).
= [3x3^-2x(-2)^6/2x3^-1x(-2)^5]^2 = 1
Answer:
1/6
Step-by-step explanation:
Step-by-step explanation:
how to help people that helps
Answer:
π/36 sec-1
Step-by-step explanation:
From the question we are given the formula below
s = rwt ..........eqn(1)
Where s= π/3m, r=3 m, t= 4 sec
We were not given value of " w" which implies we are required to find out values of" w"
We can make " w " the subject of the formula from eqn(1)
s = rwt
w= s/(rt)........eqn(2)
Then substitute for the values in eqn(2)
w= (π/3m ) / ( 3m × 4 sec)
= π/36 sec-1
Hence, the value of the
missing variable is π/36 sec-1