2 years ago

Plss I need help badly Brainliest to first answer

Mathematics

2 answers:

Hoochie [10]2 years ago

8 0

Answer:

(10,-2)

Step-by-step explanation:

N76 [4]2 years ago

3 0

(10,-2) last one I’m am correct and

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HELP!!! I NEED HELP!!!!!!

Oliga [24]

Answer:

0.0365 pounds per dollar

$2.79 per pound

$2.79 per pound is typically used

Step-by-step explanation:

13.95/5 = $2.79 per pound

5/13.95 = 0.0365 pounds per dollar

7 0

3 years ago

21 is what percent of 40

-Dominant- [34]

To solve for this, set up a proportion.
21/40 = x/100.
Cross multiply the fraction's numerators with the denominators;
21 x 100, 40 and x.
2100/40x.
Divide both numbers by 40 to get x.
2100/40 = 52.5
21 is 52.5% of 40.
I hope this helps!

5 0

3 years ago

Each week, Stephanie is paid a $180 base salary and a 3% commission on her total sales generated for the week. Which expression

ivanzaharov [21]

Answer:d

Step-by-step explanation:

Brainliest plz

8 0

2 years ago

Pls help me !!!!!!!!!!!!!!!!!!!!!!!!

Vikentia [17]

Answer:

9.89 m

Step-by-step explanation:

AC is the hypotenuse (H)

x is the opposite (O)

O and H are in sine

sin=O/H

H=O/sin

H=7.9/sin(53)

=9.89187169943418

3 SF

9.89 m

8 0

3 years ago

Read 2 more answers

Determine whether the improper integral converges or diverges, and find the value of each that converges.

shusha [124]

Answer:convergent

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int_{-\infty}^{0}1000e^xdx$

$I=1000=\int_{-\infty}^{0}e^xdx$

integration of $e^x$ is $e^x$

$I=1000\times \left [ e^x\right ]^{0}_{-\infty}$

$I=1000\times I=\left [ e^0-e^{-\infty}\right ]$

$I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]$

$I=1000\times 1=1000$

so the integration converges to 1000 units

6 0

3 years ago